原题地址:https://oj.leetcode.com/problems/combination-sum/
题意:
Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is: [7]
[2, 2, 3]
解题思路:穷举出符合条件的组合,我们一般考虑dfs。
代码:
class Solution: # @param candidates, a list of integers # @param target, integer # @return a list of lists of integers def DFS(self, candidates, target, start, valuelist): length = len(candidates) if target == 0: return Solution.ret.append(valuelist) for i in range(start, length): if target < candidates[i]: return self.DFS(candidates, target - candidates[i], i, valuelist + [candidates[i]]) def combinationSum(self, candidates, target): candidates.sort() Solution.ret = [] self.DFS(candidates, target, 0, []) return Solution.ret