Timus 1015. Test the Difference!

Timus 1015. Test the Difference! 要求将赌场中的骰子分类。

1015. Test the Difference!

Time Limit: 2.0 second
Memory Limit: 16 MB

There are N (1 ≤ N ≤ 105) dice at the casino’s "Royal Flush" storehouse. Some of them are equal, i.e. one can transform one die to another by properly rotating it. Let’s say that two dice have the same scheme if it’s possible to obtain one of them from another by a series of rotation. In other case (no rotations of the first die lead us to the second die) let’s say that dice have different schemes. Your task is to define the dice with the same scheme.

Input

The first line of the input contains the number N. Next N lines contain descriptions of the dice. Each line contains exactly one description of the die. A line describes the die in 6 numbers (separated with spaces): the number of points on the left side of the die, then on the right side, on the top, on the forward side, on the bottom and on the backward side. Certainly, those 6 numbers represent a permutation of integer numbers from 1 to 6 inclusively.

Output

The first line of the output should contain the only number Q of different die’s schemes at the storehouse. Next Q lines should contain the numbers of dice with the same scheme. To be more precisely the second line must begin with 1 and after that (separated by spaces) numbers of dice with the same as die #1 scheme must follow. We assume that all dice from the input are numbered from 1 to N. The third line (if not all the dice have the same scheme) must begin with the smallest possible number with the scheme different from the scheme of the die #1. This number (say P) is followed by numbers of dice with the same scheme as the scheme of the die #P. All next lines must be printed in the same manner. Numbers in each line of the output must be sorted in increasing order.

Sample

input output
3
1 2 6 4 5 3
4 3 6 2 5 1
4 1 3 6 2 5
2
1 2
3
Problem Source: Ural State University Internal Contest '99 #2

答案如下:

 1  using  System;
 2  using  System.IO;
 3  using  System.Collections.Generic;
 4 
 5  namespace  Skyiv.Ben.Timus
 6  {
 7     //   http://acm.timus.ru/problem.aspx?space=1 &num=1015
 8     class  T1015
 9    {
10       static   void  Main()
11      {
12         new  T1015().Run(Console.In, Console.Out);
13      }
14 
15       void  Run(TextReader reader, TextWriter writer)
16      {
17        List < int >  sort  =   new  List < int > ( 30 );
18        List < int > [] dice  =   new  List < int > [ 30 ];
19        Dictionary < int short >  dict  =  GetDict();
20         for  ( int  n  =   int .Parse(reader.ReadLine()), i  =   1 ; i  <=  n; i ++ )
21        {
22           int  q  =  dict[ int .Parse(reader.ReadLine().Replace( "   " null ))];
23           if  (dice[q]  ==   null )
24          {
25            dice[q]  =   new  List < int > ();
26            sort.Add(q);
27          }
28          dice[q].Add(i);
29        }
30        writer.WriteLine(sort.Count);
31         foreach  ( int  q  in  sort)
32        {
33           foreach  ( int  d  in  dice[q]) writer.Write(d  +   "   " );
34          writer.WriteLine();
35        }
36      }
37 
38      Dictionary < int short >  GetDict()
39      {
40         int [] qs  =  
41        {
42           123456 123465 123546 123564 123645 123654 ,
43           132456 132465 132546 132564 132645 132654 ,
44           142356 142365 142536 142563 142635 142653 ,
45           152346 152364 152436 152463 152634 152643 ,
46           162345 162354 162435 162453 162534 162543
47        };
48        Dictionary < int short >  dict  =   new  Dictionary < int short > ( 720 );
49         for  ( int  x  =   0 ; x  <   2 ; x ++ )
50           for  ( int  y  =   0 ; y  <   4 ; y ++ )
51          {
52             if  (x  ==   1   &&  (y  ==   1   ||  y  ==   3 ))  continue ;
53             for  ( int  z  =   0 ; z  <   4 ; z ++ )
54               for  ( short  q  =   0 ; q  <  qs.Length; q ++ )
55                dict.Add(Rotation(qs[q], x, y, z), q);
56          }
57         return  dict;
58      }
59 
60       int  Rotation( int  die,  int  x,  int  y,  int  z)
61      {
62         for  ( int  i  =   0 ; i  <  x; i ++ ) die  =  Rotation(die,  2 3 4 5 );
63         for  ( int  i  =   0 ; i  <  y; i ++ ) die  =  Rotation(die,  0 2 1 4 );
64         for  ( int  i  =   0 ; i  <  z; i ++ ) die  =  Rotation(die,  0 3 1 5 );
65         return  die;
66      }
67 
68       int  Rotation( int  die,  params   int [] p)
69      {
70         char [] s  =  die.ToString( " D6 " ).ToCharArray();
71         char  tmp  =  s[p[ 0 ]];
72        s[p[ 0 ]]  =  s[p[ 1 ]];
73        s[p[ 1 ]]  =  s[p[ 2 ]];
74        s[p[ 2 ]]  =  s[p[ 3 ]];
75        s[p[ 3 ]]  =  tmp;
76         return   int .Parse( new   string (s));
77      }
78    }
79  }

在本题中,总共可能有 6! = 720  种不同的输入,它们可归类到 30 种不同的骰子,每种骰子对应 24 种不同的输入。本程序中第 38 到 58 行的 GetDict() 方法就是用来将这 720 种不同的输入分为 30 种不同的骰子。变量 Dictionary<intshort> dict 的 Key 刚好遍历这 720 种不同的输入, 其 Value 的取值范围 为 0 到 29,代表 30 种不同的骰子。

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