python批量将文件夹内所有doc转成docx

doc转docx函数

import os
from win32com import client

def doc_to_docx(path):
    if os.path.splitext(path)[1] == ".doc":
        word = client.Dispatch('Word.Application')
        doc = word.Documents.Open(path)  # 目标路径下的文件
        doc.SaveAs(os.path.splitext(path)[0]+".docx", 16)  # 转化后路径下的文件
        doc.Close()
        word.Quit()

path = ""#填写文件夹路径
doc_to_docx(path)

上述代码参考至：https://blog.csdn.net/qq_16645423/article/details/79468122

获取文件夹下的所有文件的绝对路径

import os


def find_file(path, ext, file_list=[]):
    dir = os.listdir(path)
    for i in dir:
        i = os.path.join(path, i)
        if os.path.isdir(i):
            find_file(i, ext, file_list)
        else:
            if ext == os.path.splitext(i)[1]:
                file_list.append(i)
    return file_list


dir_path = ""
ext = ".doc"
file_list = find_file(dir_path, ext)

源码

import os
from win32com import client

def doc_to_docx(path):
    if os.path.splitext(path)[1] == ".doc":
        word = client.Dispatch('Word.Application')
        doc = word.Documents.Open(path)  # 目标路径下的文件
        doc.SaveAs(os.path.splitext(path)[0]+".docx", 16)  # 转化后路径下的文件
        doc.Close()
        word.Quit()

def find_file(path, ext, file_list=[]):
    dir = os.listdir(path)
    for i in dir:
        i = os.path.join(path, i)
        if os.path.isdir(i):
            find_file(i, ext, file_list)
        else:
            if ext == os.path.splitext(i)[1]:
                file_list.append(i)
    return file_list


dir_path = "C:\Users\python"#批量转换文件夹
ext = ".doc"
file_list = find_file(dir_path, ext)
for file in file_list:
    doc_to_docx(file)