Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000
For example, two is written as II
in Roman numeral, just two one's added together. Twelve is written as, XII
, which is simply X
+ II
. The number twenty seven is written as XXVII
, which is XX
+ V
+ II
.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed before V
(5) and X
(10) to make 4 and 9. X
can be placed before L
(50) and C
(100) to make 40 and 90. C
can be placed before D
(500) and M
(1000) to make 400 and 900.Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.
Example 1:
Input: "III" Output: 3
Example 2:
Input: "IV" Output: 4
Example 3:
Input: "IX" Output: 9
Example 4:
Input: "LVIII" Output: 58 Explanation: L = 50, V= 5, III = 3.
Example 5:
Input: "MCMXCIV" Output: 1994 Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
代码:
class Solution(object):
def romanToInt(self, s):
"""
:type s: str
:rtype: int
"""
key_sym = ['I', 'V', 'X', 'L', 'C', 'D', 'M']
key_val = [1, 5, 10, 50, 100, 500, 1000]
# create dict
key_dict = {}
for i in range(len(key_sym)):
key_dict[key_sym[i]] = key_val[i]
s_list = list(s)
nums = 0
while s_list:
cur_keys = []
sym_f = s_list[0]
ind_f = key_sym.index(sym_f)
# the last symbol
if len(s_list) >1:
j = 1
sym_l = s_list[j]
ind_l = key_sym.index(sym_l)
else:
ind_l = ind_f
if ind_f >= ind_l:
nums += key_dict[sym_f]
s_list.pop(0)
elif ind_f < ind_l:
nums = nums + key_dict[sym_l] - key_dict[sym_f]
s_list.pop(0)
s_list.pop(0)
return nums