1.将列表的每一个元素拼接成字符串
li = ["第一",2,"ss",55]
test = ""
for l in li :
test+=str(l)
print(test)
2.查找列表中元素，移除每个元素的空格，并查找以a或A开头并且以c结尾的所有元素
li = ["a lec", " ar ic", "A lex", "Tony ", "ra in"]
i = 0
while i3
tu=('alex', 'eric', 'rain')
print(len(tu))
print(tu[1])
print(tu[:2])
for t in tu :
print(t)
for i in range(len(tu)) :
print(i)
for i in enumerate(tu,10) :
print(i)
4
dic = {'k1': "v1", "k2": "v2", "k3": [11,22,33]}
for di in dic:
print(di)
for di in dic.values():
print(di)
for k,v in dic.items():
print(k,v)
dic.setdefault("k4","v4")
dic.update({"k1":"alex"})
dic.get("k3").append(44)
dic.get("k3").insert(0,18)
for k,v in dic.items():
print(k,v)
5将列表li = ["alex", "seven"]转换成字典且字典的key按照10开始向后递增
li = ["alex", "seven"]
tu = {}
for k,v in enumerate(li,10):
tu[k]=v
print(tu)
6有如下值集合[11,22,33,44,55,66,77,88,99,90]，将所有大于66的值保存至字典的第一个key中，将小于66的值保存至第二个key的值中。
即：{'k1':大于66的所有值, 'k2':小于66的所有值}
li = [11,22,33,44,55,66,77,88,99,90]
sorut = {"k1":[],"k2":[],}
for l in li :
if l>66 :
sorut["k1"].append(l)
elif l<66 :
sorut["k2"].append(l)
else:
pass
print(sorut)
7输出商品列表，用户输入序号，显示用户选中的商品
商品li = ["手机", "电脑", '鼠标垫', '游艇']
允许用户添加商品
用户输入序号显示内容
li = ["手机", "电脑", '鼠标垫', '游艇']
print('商品列表'.center(20,'-'))
i=0
re =True
# while ilen(li):
print("序号错误！")
num = input("请重新输入序号：")
else:
print(li[int(num)-1])
re=False
else:
print("请输入正确操作！")
while i8
for ran in range(1,101):
print(ran)
for ran in range(100,0,-1):
print(ran)
i = 0;
while i<100:
i+=1
print(i)
a=100
while a>0:
print(a)
a-=1
9 9x9
for i in range(1,10):
for j in range(1,i+1):
print(str(j)+"X"+str(i)+"="+str(i*j),end=" ")
print()
10 一百以内的素数
trun = True
ret = []
for i in range(1,101):
j=2
while trun and j 冒泡
li = [1,3,2,7,6,23,41,24,33,85,56]
temp = 0
for l in range(0,len(li)):
for j in range(0,l):
if li[j]>li[l]:
li[l],li[j]=li[j],li[l]
print(li)
公鸡母鸡小鸡 100元
公鸡 = 5
母鸡 = 3
小鸡 = 2
for g in range(1,20):
for m in range(1,33):
for x in range(1, 50):
if 5*g+3*m+2*x==100:
print(g,m,x)
