(LintCode) No 2: Fabonacci

题目描述：输出对应的第几项数值。

代码如下：

class Solution {
public:
    /**
     * @param n: an integer
     * @return: an ineger f(n)
     */
    int fibonacci(int n) {
        // write your code here
        int a = 0, b = 1;
        for(int i = 1; i < n; i++)
        {
            int c = a + b;
            a = b;
            b = c;
        }
        return a;
    }
};