上篇文章写了如何在处理单列相同数据时让相同的项进行自动合并, 如果有多列合并的需求我们也应该可以从容应对...
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废话不多说 上代码
HTML
JS
var Main = {
data() {
return {
tableData6: [{
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂1',
amount3: 10
}, {
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂2',
amount3: 12
}, {
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂3',
amount3: 9
}, {
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂1',
amount3: 17
}, {
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂2',
amount3: 15
},{
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂3',
amount3: 10
}, {
name: '部门1总计',
type: 1,
amount1: '部门1跟单员',
amount2: '',
amount3: 12
},{
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂1',
amount3: 10
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂2',
amount3: 12
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂3',
amount3: 9
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂1',
amount3: 17
}, {
name: '部门2',
type: 0,
amount1: '跟单员4',
amount2: '成衣工厂2',
amount3: 15
},{
name: '部门2',
type: 0,
amount1: '跟单员4',
amount2: '成衣工厂3',
amount3: 10
}, {
name: '部门2总计',
type: 1,
amount1: '部门2跟单员',
amount2: '',
amount3: 12
}],
arr1:[],
arr2:[]
};
},
created() {
this.setdates(this.tableData6)
},
methods: {
setdates(arr) {
var obj = {},
k, arr1 = [];
for(var i = 0, len = arr.length; i < len; i++) {
k = arr[i].name;
if(obj[k])
obj[k]++;
else
obj[k] = 1;
}
console.log(obj)
//保存结果{el-'元素',count-出现次数}
for(var o in obj) {
for(let i=0;i 0 ? 1 : 0
return [_row,_col]
}else if(columnIndex === 0 && this.tableData6[rowIndex].type == 1){
return [1,3]
}else if (columnIndex === 1 && this.tableData6[rowIndex].type == 1){
return [0,0]
}else if (columnIndex === 2 && this.tableData6[rowIndex].type == 1){
return [0,0]
}else if (columnIndex === 1 && this.tableData6[rowIndex].type == 0){
let _row = this.arr2[rowIndex]
let _col = this.arr2[rowIndex] > 0 ? 1 : 0
return [_row,_col]
}
}
}
};
var Ctor = Vue.extend(Main)
new Ctor().$mount('#app')
最终效果
Fiddle代码预览地址https://jsfiddle.net/Tomatoro...
可能需要翻(程序员必备)