超市有自助结账的队列。您的任务是编写一个函数来计算所有客户签出所需的总时间!
###输入
###输出
该函数应返回一个整数,即所需的总时间。
##重要
请查看下面的示例和说明,以确保您正确理解任务:)
### 例子
queueTime([5,3,4],1)
//应该返回12
//因为当有1个时,总时间就是时间的总和
queueTime([10,2,3,3],2)
//应该返回10
//因为这里n = 2,而第二,第三和第四人在
//队列在第一个人完成之前完成。
queueTime([2,3,10],2)
//应该返回12
queue_time([5,3,4],1)
#应该返回12
#因为当n = 1时,总时间只是时间的总和
queue_time([10,2,3,3],2)
#应该返回10
#因为这里n = 2,而第二,第三和第四人在
#rief在第一个人完成之前完成。
queue_time([2,3,10],2)
#应该返回12
queue_time([5,3,4],1)
#应该返回12
#因为当n = 1时,总时间只是时间的总和
queue_time([10,2,3,3],2)
#应该返回10
#因为这里n = 2,而第二,第三和第四人在
#rief在第一个人完成之前完成。
queue_time([2,3,10],2)
#应该返回12
queueTime(std :: vector {5,3,4},1)
//应该返回12
//因为当n = 1时,总时间只是时间的总和
queueTime(std :: vector {10,2,3,3},2)
//应该返回10
//因为这里n = 2,而第二,第三和第四人在
//队列在第一个人完成之前完成。
queueTime(std :: vector {2,3,10},2)
//应该返回12
###澄清
*只有一个队列服务很多,并且
*队列的顺序永远不会改变,和
*队列中的前面人员(即数组矩阵/列表中的第一个元素)一旦变为空闲就进入一个直到。
注:您应该假设所有测试输入都是有效的,如上所述。
附:这个kata的情况可以比作与线程池更加计算机科学相关的想法,与同时运行多个进程有关:https://en.wikipedia.org/wiki/Thread_pool
There is a queue for the self-checkout tills at the supermarket. Your task is write a function to calculate the total time required for all the customers to check out!
The function should return an integer, the total time required.
Please look at the examples and clarifications below, to ensure you understand the task correctly
queueTime([5,3,4], 1)
// should return 12
// because when there is 1 till, the total time is just the sum of the times
queueTime([10,2,3,3], 2)
// should return 10
// because here n=2 and the 2nd, 3rd, and 4th people in the
// queue finish before the 1st person has finished.
queueTime([2,3,10], 2)
// should return 12
queue_time([5,3,4], 1)
# should return 12
# because when n=1, the total time is just the sum of the times
queue_time([10,2,3,3], 2)
# should return 10
# because here n=2 and the 2nd, 3rd, and 4th people in the
# queue finish before the 1st person has finished.
queue_time([2,3,10], 2)
# should return 12
queue_time([5,3,4], 1)
# should return 12
# because when n=1, the total time is just the sum of the times
queue_time([10,2,3,3], 2)
# should return 10
# because here n=2 and the 2nd, 3rd, and 4th people in the
# queue finish before the 1st person has finished.
queue_time([2,3,10], 2)
# should return 12
queueTime(std::vector<int>{5,3,4}, 1)
// should return 12
// because when n=1, the total time is just the sum of the times
queueTime(std::vector<int>{10,2,3,3}, 2)
// should return 10
// because here n=2 and the 2nd, 3rd, and 4th people in the
// queue finish before the 1st person has finished.
queueTime(std::vector<int>{2,3,10}, 2)
// should return 12
N.B. You should assume that all the test input will be valid, as specified above.
P.S. The situation in this kata can be likened to the more-computer-science-related idea of a thread pool, with relation to running multiple processes at the same time: https://en.wikipedia.org/wiki/Thread_pool
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