238. Product of Array Except Self

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i].

Solve it without division and in O(n).

For example, given [1,2,3,4], return [24,12,8,6].

Follow up:
Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.)

Solution:

public class Solution 
{
    public int[] productExceptSelf(int[] nums) 
    {
        int[] result = new int[nums.length];
        
        int temp = 1;
        for(int i = 0; i < nums.length; i ++)
        {
            result[i] = temp;
            temp *= nums[i];
        }
        
        temp = 1;
        for(int i = nums.length - 1; i >= 0; i --)
        {
            result[i] = result[i] * temp;
            temp *= nums[i];
        }
        return result;
    }
}