LeetCode 35. Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

题意：把给的数字插入到，应该插入的位置，返回下标

java代码：

public int searchInsert(int[] nums, int target) {
        if (nums == null || nums.length == 0 || nums[0] >= target) return 0;

        if (nums[nums.length - 1] == target) return nums.length - 1;

        if (nums[nums.length - 1] < target) return nums.length;

        for (int i = 0; i < nums.length - 1; i++) {
            if (i == nums.length - 1) break;
            if (nums[i] <= target && nums[i + 1] >= target) return i + 1;
        }
        return -1;
    }