单向链表逆序

一则面试题：写一个方法，讲一个单向链表逆序。

#include  
#include 
typedef struct Node 
{
    int data; 
    struct Node *next; 
}Node;

//创建链表
Node *creat(int n)   //n为节点个数
{
    Node *head, *p, *s; 
    int i; 
    p = head = (Node *)malloc(sizeof(Node)); 
    for(i = 1;i <= n;i++) 
    { 
        s = (Node *)malloc(sizeof(Node)); 
        scanf("%d",  &s->data); 
        p->next = s; 
        p = s; 
    } 
    p->next = NULL; 
    return head; 
} 

//原地置换 
void reverse(Node *head)
{    
    Node *p,*s,*t; 
    p = head; 
    s = p->next; 
    //主要置换过程
    while(s->next != NULL) 
    {        
        t = s->next; 
        s->next = p; 
        p = s; 
        s = t; 
    } 
    s->next = p; 
    head->next->next = NULL;  //收尾 
    head->next = s;  //赋头 
} 

//显示链表内容
void display(Node *head) 
{ 
    Node *p; 
    p = head->next; 
    while(p != NULL) 
    {        
        printf("%d ",p->data); 
        p = p->next; 
    } 
    printf("\n"); 
} 
int main() 
{
     int n;
     Node *head; 
     printf("请输入链表节点数:");
     scanf("%d",&n);
     head = creat(n);
     printf("原链表：\n"); 
     display(head); 
     reverse(head); 
     printf("置换后链表：\n"); 
     display(head); 
}

运行：

请输入链表节点数:5
11 22 33 44 55
原链表：
11 22 33 44 55 
置换后链表：
55 44 33 22 11