LeetCode-83~Remove Duplicates from Sorted List

Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
给定一个排好序的链表，删除所有重复的元素。

算法分析

本题重点在给定的链表已经排序，因此只要从头开始删除重复的元素即可，即current.val == current.next.next，就删除，current.next = current.next.next。

Java代码

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        ListNode current = head;
        while (current != null && current.next != null) {//
            if (current.val != current.next.val) {
                current = current.next;
            } else {
                current.next = current.next.next;
            }
        }
        return head;
    }
}