url中取某一个参数的值&清除cookie

  var str="http://toutiao.com/yl.html?f=88&m=988"
  var kv = function(key) {
            var _key = new RegExp("[?&]" + key + "\=([^&#]+)", "g").exec(str);
            if (_key) {
                return _key[1]
            };
        }
    
console.log(kv ("m"))  //988
    

清除cookie

//清除所有domain下的cookie
 function removeCookies(key) {
            $.removeCookie(key);
            $.removeCookie(key, {
                path: '/',
                domain: 'baidu.com'
            });
            $.removeCookie(key, {path: '/'});
        }
        if($.cookie("q")){
            removeCookies('q');
        };