python实现将列表中各个值快速赋值给多个变量

我就废话不多说啦，还是直接看代码吧！

list1 = [1,2,3,4]
a,b,c,d = list1

则

a = 1
b =2

等

这种方式只有当左边的操作数个数和list1长度相同时,才可以这么做,不然报错.

我们假设我们有一个list对象List,它的长度足够长,想把它从下标i开始的k个元素赋给k个元素,可以这么做:

v1, v2, v3, …, vk = List[i : i + k] #默认i=0, k=len(List)

补充知识：python 将某个字段存储为列表类型

实现存储数据格式为

{
    "_index": "nested-20180815",
    "_type": "stb-iptv-montor-m-gather-apk",
    "_id": "AWU8sZboGQQbsn0rAW4J",
    "_score": 1,
    "_source": {
     "mdiNested": [
      {
       "mdiMLR": 0,
       "mdiType": "0"
      },
      {
       "mdiMLR": 0,
       "mdiType": "1"
      },
      {
       "mdiMLR": 0,
       "mdiType": "2"
      },
      {
       "mdiMLR": 0,
       "mdiType": "3"
      },
      {
       "mdiMLR": 0,
       "mdiType": "4"
      },
      {
       "mdiMLR": 0,
       "mdiType": "5"
      }
     ]
    }
   }

代码：

from elasticsearch import Elasticsearch
from elasticsearch import helpers
import json

es_20 = Elasticsearch(hosts="1.0.0.0", port=9200, timeout=15000)
time_ = "20180815"
index_20 = "nested-{0}".format(time_)
type_20 = "stb-iptv-montor-m-gather-apk"


def set_mapping():
  my_mappping = {
    type_20: {
      "properties": {
        "mdiNested": {
          "properties": {
            "mdiMLR": {
              "type": "short"
            },
            "mdiType": {
              "type": "keyword"
            }
          }
        }
      }
    }
  }
  create_index = es_20.indices.create(index=index_20, body=None)
  create_mapping = es_20.indices.put_mapping(index=index_20, body=my_mappping, doc_type=type_20)
  mdiMLR = [0,1,2,3,4]
  mdiType = ["0","1","2","3","4","5"]
  actions = []
  dict_ ={}
  for mdiMLR_ in mdiMLR:
    dict_list = []
    for type in mdiType:
      t1 ={'mdiMLR': mdiMLR_, 'mdiType': type}
      dict_list.append(t1)
    action = {
        "_index": index_20,
        "_type": type_20,
        "_source": {
          "mdiNested": dict_list
        }
    }
    actions.append(action)
  helpers.bulk(es_20, actions)

以上这篇python实现将列表中各个值快速赋值给多个变量就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持脚本之家。