Living one day at a time (update for a long time)

1,  http://acm.hdu.edu.cn/showproblem.php?pid=1228    2014-04-14  10:39:52

分析:字符串处理题。。。

Living one day at a time (update for a long time)
#include<iostream>

#include<cstdio>

#include<cstring>

#include<cstdlib>

#include<cstring>

#include<map>



using namespace std;



map<string,int> mp;



void init(){

    mp["zero"]=0;  mp["one"]=1;   mp["two"]=2;   mp["three"]=3;

    mp["four"]=4;  mp["five"]=5;  mp["six"]=6;   mp["seven"]=7;

    mp["eight"]=8; mp["nine"]=9;  mp["+"]=0;     mp["="]=0;

}





int main(){



    //freopen("input.txt","r",stdin);



    char str[1100];

    init();



    while(~scanf("%s",str)){



        int ans=0;

        int tmp1=0,tmp2=0;

        int flag=0;

        tmp1=mp[str];

        while(scanf("%s",str) && strcmp(str,"=")!=0){

            if(strcmp(str,"+")==0){

                flag=1;

                continue;

            }

            if(flag==0){

                tmp1=tmp1*10+mp[str];

            }else{

                tmp2=tmp2*10+mp[str];

            }

        }

        ans=tmp1+tmp2;

        if(ans==0)

            break;

        printf("%d\n",ans);

    }



    return 0;

}
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2,  http://acm.hdu.edu.cn/showproblem.php?pid=1229    2014-04-14  10:48:57

分析:easy题。。。

Living one day at a time (update for a long time)
#include<iostream>

#include<cstdio>

#include<cstring>

#include<cstdlib>

#include<cstring>

#include<map>



using namespace std;



int main(){

    

//    freopen("input.txt","r",stdin);



    int a,b,k;

    while(~scanf("%d%d%d",&a,&b,&k)){

        int tmp=1;

        if(a+b==0)

            break;

        while(k!=0){

            tmp*=10;

            k--;

        }

        if(a%tmp-b%tmp==0){

            printf("-1\n");

        }else{

            printf("%d\n",a+b);    

        }

    }

    return 0;

}
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