看一段简单的代码,在一个pager里面显示两个TextView
List items = new ArrayList();
adapter = new MyPagerAdapter();
TextView tv = new TextView(getActivity());
tv.setText("第一页");
items.add(tv);
tv = new TextView(getActivity());
tv.setText("第二页");
items.add(tv);
pager.setAdapter(adapter);
Adapter代码
class MyPagerAdapter extends PagerAdapter{
@Override
public Object instantiateItem(ViewGroup container, int position) {
View layout = items.get(position);
container.addView(layout);
return layout;
}
@Override
public void destroyItem(ViewGroup container, int position, Object object) {
View layout = items.get(position);
container.removeView(layout);
}
@Override
public boolean isViewFromObject(View arg0, Object arg1) {
return arg0 == arg1;
}
@Override
public int getCount() {
return items.size();
}
@Override
public int getItemPosition(Object object) {
// TODO Auto-generated method stub
return super.getItemPosition(object);
}
}
代码运行正常,左右滑动都OK。
好,现在需求来了,我需要把“第一页”和“第二页”干掉,再重新添加两个TextView,分别是“第三页”和“第四页”,于是按常理写了如下代码
items.clear();
TextView tv = new TextView(getActivity());
tv.setText("第三页");
items.add(tv);
tv = new TextView(getActivity());
tv.setText("第四页");
items.add(tv);
adapter.notifyDataSetChanged();
我们在使用ListView的时候,改变数据源的数据,然后通知adpater去更新,就可以正常显示,可是在ViewPager这不好使,上面代码执行后,没有任何变化
那我们想是不是ViewPager需要清一下原有的试图呢,好,再加一句
pager.removeAllViews();
再次运行,可好,一片空白,啥也没了,真干净!
蒙了吧,到底什么原因,就是getItemPosition,让我看看当ViewPager的Adapter发生变化时,到底干了啥,Adapter执行notifyDataSetChanged时,会触发ViewPager的dataSetChanged方法,下面是源码,:
void dataSetChanged() {
// This method only gets called if our observer is attached, so mAdapter is non-null.
final int adapterCount = mAdapter.getCount();
mExpectedAdapterCount = adapterCount;
boolean needPopulate = mItems.size() < mOffscreenPageLimit * 2 + 1 &&
mItems.size() < adapterCount;
int newCurrItem = mCurItem;
boolean isUpdating = false;
for (int i = 0; i < mItems.size(); i++) {
final ItemInfo ii = mItems.get(i);
final int newPos = mAdapter.getItemPosition(ii.object);
//看这句话,如果是PagerAdapter.POSITION_UNCHANGED标志,直接返回,不做任何处理
if (newPos == PagerAdapter.POSITION_UNCHANGED) {
continue;
}
//只有返回PagerAdapter.POSITION_NONE标志时,才会对内部视图进行调整
if (newPos == PagerAdapter.POSITION_NONE) {
//先从数据源中清除
mItems.remove(i);
i--;
if (!isUpdating) {
mAdapter.startUpdate(this);
isUpdating = true;
}
//在调用Adapter的destroyItem,去销毁视图
mAdapter.destroyItem(this, ii.position, ii.object);
needPopulate = true;
if (mCurItem == ii.position) {
// Keep the current item in the valid range
newCurrItem = Math.max(0, Math.min(mCurItem, adapterCount - 1));
needPopulate = true;
}
continue;
}
if (ii.position != newPos) {
if (ii.position == mCurItem) {
// Our current item changed position. Follow it.
newCurrItem = newPos;
}
ii.position = newPos;
needPopulate = true;
}
}
if (isUpdating) {
mAdapter.finishUpdate(this);
}
Collections.sort(mItems, COMPARATOR);
if (needPopulate) {
// Reset our known page widths; populate will recompute them.
final int childCount = getChildCount();
for (int i = 0; i < childCount; i++) {
final View child = getChildAt(i);
final LayoutParams lp = (LayoutParams) child.getLayoutParams();
if (!lp.isDecor) {
lp.widthFactor = 0.f;
}
}
setCurrentItemInternal(newCurrItem, false, true);
requestLayout();
}
}
PagerAdapter.POSITION_UNCHANGED,这个标记决定着视图是否被重新创建,Apdapter默认的代码如下
public int getItemPosition(Object object) {
return POSITION_UNCHANGED;
}
默认返回POSITION_UNCHANGED,所以如果你不对Adapter的getItemPosition进行重写的画,就会出现无法更改内部视图效果的问题。下面对从PagerAdapter继承的代码进行改造,加上对getItemPosition的修改,让他直接返回POSITION_NONE,POSITION_NONE每次数据发生变化,都会引起视图的重建,比较消耗内存,所以不需要变化内部视图时,避免使用。
@Override
public int getItemPosition(Object object) {
// TODO Auto-generated method stub
return POSITION_NONE;
}
如果返回了POSITION_NONE,但是没有pager.removeAllViews(),那么“第一页”和“第二页”没有消失,“第三页”和“第四页”也上去了,分别和前两页重合了,看图