树链剖分应用题,看到一群大佬各种LCT,Splay,瑟瑟发抖ing
#include
using namespace std;
typedef long long ll;
typedef pair pii;
const int N = 2e5;
int fa[N],lv[N],siz[N],son[N],top[N],dfn[N],ptn[N],cnt=0;
vector G[N];
int n,seg[N<<2];
void build(int l,int r,int p) {
if(l==r) {
seg[p]=INT_MAX;
return;
}
int m=(l+r)/2;
build(l,m,p<<1);
build(m+1,r,p<<1|1);
seg[p]=min(seg[p<<1],seg[p<<1|1]);
}
int query(int s,int t,int l,int r,int p) {
if(s<=l&&r<=t) return seg[p];
int m=(l+r)/2;
if(t<=m) return query(s,t,l,m,p<<1);
if(m+1<=s) return query(s,t,m+1,r,p<<1|1);
return min(query(s,t,l,m,p<<1),query(s,t,m+1,r,p<<1|1));
}
void update(int pos,int l,int r,int p){
if(l==r) {
if(seg[p]==INT_MAX) seg[p]=pos;
else seg[p] = INT_MAX;
return;
}
int m=(l+r)/2;
if(pos<=m) update(pos,l,m,p<<1);
else update(pos,m+1,r,p<<1|1);
seg[p]=min(seg[p<<1],seg[p<<1|1]);
}
int dfs1(int x,int fx) {
son[x]=-1;
siz[x]=1;
fa[x]=fx;
lv[x]=lv[fx]+1;
for(auto p:G[x]) {
int to = p;
if(to==fx) continue;
siz[x] += dfs1(to,x);
if(son[x] == -1 || siz[to] > siz[son[x]]) son[x] = to;
}
return siz[x];
}
void dfs2(int x,int root) {
top[x]=root;
dfn[x]=++cnt;
ptn[dfn[x]]=x;
if(son[x]==-1) return;
dfs2(son[x],root);
for(auto p:G[x]) {
int to = p;
if(to == son[x] || to == fa[x]) continue;
dfs2(to,to);
}
}
int ask(int x,int y) {
int ans=INT_MAX;
while(top[x]!=top[y]) {
if(lv[top[x]]>lv[top[y]]) swap(x,y);
ans=min(ans, query(dfn[top[y]], dfn[y],1,n,1));
y=fa[top[y]];
}
if(dfn[x]!=dfn[y]) {
if(dfn[x]>dfn[y]) swap(x,y);
ans = min(ans, query(dfn[x],dfn[y],1,n,1));
}
if(ans == INT_MAX) return -1;
return ptn[ans];
}
int a,b,c,q,x,o;
int main(){
memset(seg,0,sizeof(seg));
cnt = 0;
scanf("%d %d",&n,&q);
for(int i=1;i<=n;i++) G[i].clear();
for(int i=1;i