检测网页是否正常打开

2019独角兽企业重金招聘Python工程师标准>>>

import urllib.request  
import time  
  
opener = urllib.request.build_opener()  
opener.addheaders = [('User-agent', 'Mozilla/49.0.2')]  
#这个是你放网址的文件名，改过来就可以了  
# file = open('test.txt')  
# lines = file.readlines()  
aa=['http://www.jd.com/','https://top.jd.com/?cateId=794&itemId=6254701']  
# for line in lines:  
#     temp=line.replace('\n','')  
#     aa.append(temp)  
# print(aa)  
  
print('开始检查：')  
for a in aa:  
    tempUrl = a  
    try :  
        opener.open(tempUrl)  
        print(tempUrl+'没问题')  
    except urllib.error.HTTPError:  
        print(tempUrl+'=访问页面出错')  
        time.sleep(2)  
    except urllib.error.URLError:  
        print(tempUrl+'=访问页面出错')  
        time.sleep(2)  
    time.sleep(0.1)  

转载于:https://my.oschina.net/u/3371661/blog/1820935