vc++获取char*中的数字，排序后输出

void MyOutPut(char *str)
{
	char *temp = str;
	bool lastNum = false;
	int aggr[100] = {0};
	int len = 0;
	int nIndex = 0;
	//获取所有的数字
	while(*temp)
	{
		if(*temp >= '0' && *temp <= '9')
		{
			if(!lastNum)
			{
				aggr[nIndex] = *temp - 48;
				nIndex++;
			}
			else
			{
				aggr[nIndex - 1] = aggr[nIndex - 1] * 10 + *temp - 48;
			}
			lastNum = true;
		}
		else
		{
			lastNum = false;
		}
		*temp++;
	}
	//排序
	for(int i = 0 ; i < nIndex; ++i)
	{
		for(int j = 0;j < nIndex - i - 1; ++j)
		{
			if(aggr[j] > aggr[j + 1])
			{
				int nMax = aggr[j];
				aggr[j] = aggr[j + 1];
				aggr[j + 1] = nMax;
			}
		}
	}
	//输出
	for(int i = 0; i < nIndex - 1; i++)
	{
		printf("%d-", aggr[i]);
	}
	printf("%d", aggr[nIndex - 1]);
	printf("\n");
}