判断一个点是否在圆内（三点确定一个圆）

三角形的外接圆圆心是任意两边的垂直平分线的交点。 三角形外接圆圆心叫外心。

                 /// 

		/// Returns true if the point (p) lies inside the circumcircle made up by points (p1,p2,p3)
		/// 
		/// 
		/// NOTE: A point on the edge is inside the circumcircle
		/// 
		/// Point to check
		/// First point on circle
		/// Second point on circle
		/// Third point on circle
		/// true if p is inside circle
		private static bool InCircle(Geometry.Point p, Geometry.Point p1, Geometry.Point p2, Geometry.Point p3)
		{
			//Return TRUE if the point (xp,yp) lies inside the circumcircle
			//made up by points (x1,y1) (x2,y2) (x3,y3)
			//NOTE: A point on the edge is inside the circumcircle

			if (System.Math.Abs(p1.Y - p2.Y) < double.Epsilon && System.Math.Abs(p2.Y - p3.Y) < double.Epsilon)
			{
				//INCIRCUM - F - Points are coincident !!
				return false;
			}

			double m1, m2;
			double mx1, mx2;
			double my1, my2;
			double xc, yc;
						
			if (System.Math.Abs(p2.Y - p1.Y) < double.Epsilon)
			{
				m2 = -(p3.X - p2.X) / (p3.Y - p2.Y);
				mx2 = (p2.X + p3.X) * 0.5;
				my2 = (p2.Y + p3.Y) * 0.5;
				//Calculate CircumCircle center (xc,yc)
				xc = (p2.X + p1.X) * 0.5;
				yc = m2 * (xc - mx2) + my2;
			}
			else if (System.Math.Abs(p3.Y - p2.Y) < double.Epsilon)
			{
				m1 = -(p2.X - p1.X) / (p2.Y - p1.Y);
				mx1 = (p1.X + p2.X) * 0.5;
				my1 = (p1.Y + p2.Y) * 0.5;
				//Calculate CircumCircle center (xc,yc)
				xc = (p3.X + p2.X) * 0.5;
				yc = m1 * (xc - mx1) + my1;
			}
			else
			{
				m1 = -(p2.X - p1.X) / (p2.Y - p1.Y);
				m2 = -(p3.X - p2.X) / (p3.Y - p2.Y);
				mx1 = (p1.X + p2.X) * 0.5;
				mx2 = (p2.X + p3.X) * 0.5;
				my1 = (p1.Y + p2.Y) * 0.5;
				my2 = (p2.Y + p3.Y) * 0.5;
				//Calculate CircumCircle center (xc,yc)
				xc = (m1 * mx1 - m2 * mx2 + my2 - my1) / (m1 - m2);
				yc = m1 * (xc - mx1) + my1;
			}

			double dx = p2.X - xc;
			double dy = p2.Y - yc;
			double rsqr = dx * dx + dy * dy;
			//double r = Math.Sqrt(rsqr); //Circumcircle radius
			dx = p.X - xc;
			dy = p.Y - yc;
			double drsqr = dx * dx + dy * dy;

			return (drsqr <= rsqr);
		}