poj2388 Who's in the Middle

见到水题就高兴… 不过好像这样也没什么提高

题解就直接写在前面了，题意就是给你n个数 然后让你找出中间的那个数，直接用sort排起来输出中间的就好了 或者我记得以前接触stl的时候有个可以只排一部分的函数，可以节省点时间 不过对这个题来说全排就足够了

Who's in the Middle

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 40851		Accepted: 23649

Description

FJ is surveying his herd to find the most average cow. He wants to know how much milk this 'median' cow gives: half of the cows give as much or more than the median; half give as much or less. 

Given an odd number of cows N (1 <= N < 10,000) and their milk output (1..1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.

Input

* Line 1: A single integer N 

* Lines 2..N+1: Each line contains a single integer that is the milk output of one cow.

Output

* Line 1: A single integer that is the median milk output.

Sample Input

5
2
4
1
3
5

Sample Output

3

Hint

INPUT DETAILS: 

Five cows with milk outputs of 1..5 

OUTPUT DETAILS: 

1 and 2 are below 3; 4 and 5 are above 3.

源代码：

#include
#include
#include
using namespace std;

int main()
{
	int n;
	while(cin>>n)
	{
		int num[n+1];
		for(int i=0;i>num[i];
		sort(num,num+n);
		cout<