django实现文件上传代码

使用open()进行上传

def upload(request):
    content=request.FILES['file']
    if not content:
        return HttpResponse('无文件')
    uu="".join(str(uuid.uuid4()).split('-'))
    filename=uu+"."+(content.name).split('.',)[-1]
    de= open(os.path.join('static','uploadfile',filename),'wb+')
    for chunk in content.chunks():
        de.write(chunk)
    de.close()


    return HttpResponse("上传成功")

 

使用django模块进行文件上传

import os
from django.core.files.storage import FileSystemStorage
def upload(request):
    content=request.FILES['file']
    if not content:
        return HttpResponse('无文件')
    f2=FileSystemStorage()
    r=f2.save('static/uploadfile/%s'%(content.name),content)#返回文件名，如果文件名存在则会创建一个不重复的名称


    return HttpResponse('上传成功')