C语言实现，解决八皇后问题

《c和指针》上的一道题，对提示中的回溯算法不太明白，等有时间了好好看看。自己整的一个递归的解，繁琐一点，但是是正解，回头也再优化下。

 

 

流程图

代码

 

/* CheckNqueens.c */

#include 

#define DIM 8
#define NUM 8

static int array[DIM][DIM]; // 0 --> OK, 1 --> Queen, -1 --> not OK;

static void CopyIntArray(int * t, const int * s, int num); //copy int array from s to t;
static int IsOk(int pos);  //is previous queen affected: 1 Not, 0 Yes
static void AddNotOkPos(int pos);
static void PrintArray();

int CheckNqueens(int pos)
{
	static int count;     // count for solutions
	static int numok;     // count for queen positions, if == 8, to print chessboard;
	int temp[DIM][DIM];
	CopyIntArray(&temp[0][0], &array[0][0], DIM*DIM);
	
	while( pos < DIM*DIM ){
		
		int x, y;
		x = pos / DIM;
		y = pos % DIM;

		if(array[x][y] != -1)
			if(IsOk(pos)){
				
				array[x][y] = 1;
				AddNotOkPos(pos);
				
				if(++ numok == NUM){
					PrintArray();
					count++;	
				}else
					CheckNqueens(pos+1);
				
				numok--;
				CopyIntArray(&array[0][0],&temp[0][0],DIM*DIM);
			}
		
		pos++;		
	}
	
	return count;
	
}

void CopyIntArray(int * t, const int * s, int num)
{
	int i = 0;
	while(i++= 0 && j >= 0)
		if(array[i--][j--]== 1)
			return 0;
	
	//upper right
	i = x, j = y;
	while( i < DIM && j >= 0)
		if(array[i++][j--]== 1)
			return 0;
	
	//lower left
	i = x, j = y;
	while( i >= 0 && j < DIM)
		if(array[i--][j++]== 1)
			return 0;
			
	//lower right
	i = x, j = y;
	while( i < DIM && j < DIM)
		if(array[i++][j++]== 1)
			return 0;
	
	return 1;	
}

/* calculting each affected position in array = -1 */
void AddNotOkPos(int pos)
{
	int x,y,i,j;
	x = pos / DIM;
	y = pos % DIM;
	
	//horizontal;
	i = 0, j = y;
	while(i < DIM)
		array[i++][j] = -1;
	
	//vertical;
	i = x, j = 0;
	while(j < DIM)
		array[i][j++] = -1;

	//upper left		
	i = x, j = y;
	while( i >= 0 && j >= 0)
		array[i--][j--] = -1;
	
	//upper right
	i = x, j = y;
	while( i < DIM && j >= 0)
		array[i++][j--] = -1;
	
	//lower left
	i = x, j = y;
	while( i >= 0 && j < DIM)
		array[i--][j++] = -1;
			
	//lower right
	i = x, j = y;
	while( i < DIM && j < DIM)
		array[i++][j++] = -1;
	
	array[x][y] = 1;	
}

//to print the chessboard available
void PrintArray()
{
	int i, j;
	for(i = 0; i < DIM; i++){
		for(j = 0; j < DIM; j++)
			if(array[i][j] == 1)
				putchar('O');
			else
				putchar('*');
		putchar('\n');
	}
	putchar('\n');			
}