题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=&problem=3146&mosmsg=Submission+received+with+ID+14262472
There is a bag-like data structure, supporting two operations:
1 x
Throw an element x into the bag.
2
Take out an element from the bag.
Given a sequence of operations with return values, you're going to guess the data structure. It is a stack (Last-In, First-Out), a queue (First-In, First-Out), a priority-queue (Always take out larger elements first) or something else that you can hardly imagine!
There are several test cases. Each test case begins with a line containing a single integer n (1<=n<=1000). Each of the next n lines is either a type-1 command, or an integer 2 followed by an integer x. That means after executing a type-2 command, we get an element x without error. The value of x is always a positive integer not larger than 100. The input is terminated by end-of-file (EOF). The size of input file does not exceed 1MB.
For each test case, output one of the following:
stack
It's definitely a stack.
queue
It's definitely a queue.
priority queue
It's definitely a priority queue.
impossible
It can't be a stack, a queue or a priority queue.
not sure
It can be more than one of the three data structures mentioned above.
6 1 1 1 2 1 3 2 1 2 2 2 3 6 1 1 1 2 1 3 2 3 2 2 2 1 2 1 1 2 2 4 1 2 1 1 2 1 2 2 7 1 2 1 5 1 1 1 3 2 5 1 4 2 4
queue not sure impossible stack priority queue
题目意思很简单,思路也很简单,直接模拟判断就是啦。。。。。
code:
#include
#include
#include
#include
#include
#include
#include
using namespace std;
const int maxn=1010;
int a[maxn],b[maxn];
int n;
bool fs()
{
stack s;
for(int i=1;i<=n;i++)
{
if(a[i]==1)
{
s.push(b[i]);
}
else
{
if(s.empty()) return false;
int d=s.top();
if(d!=b[i])
{
return false;
}
else
{
s.pop();
}
}
}
return true;
}
bool fq()
{
queue q;
for(int i=1;i<=n;i++)
{
if(a[i]==1)
{
q.push(b[i]);
}
else
{
if(q.empty()) return false;
int d=q.front();
if(d!=b[i])
{
return false;
}
else
{
q.pop();
}
}
}
return true;
}
bool fQ()
{
priority_queue,less >Q;
for(int i=1;i<=n;i++)
{
if(a[i]==1)
{
Q.push(b[i]);
}
else
{
if(Q.empty()) return false;
int d=Q.top();
if(d!=b[i])
{
return false;
}
else
{
Q.pop();
}
}
}
return true;
}
int main()
{
while(scanf("%d",&n)==1)
{
for(int i=1;i<=n;i++)
{
scanf("%d%d",&a[i],&b[i]);
}
bool flag1=fs(),flag2=fq(),flag3=fQ();
if(flag1==false&&flag2==false&&flag3==false)
{
printf("impossible\n");
}
else if(flag1==true&&flag2==false&&flag3==false)
{
printf("stack\n");
}
else if(flag1==false&&flag2==true&&flag3==false)
{
printf("queue\n");
}
else if(flag1==false&&flag2==false&&flag3==true)
{
printf("priority queue\n");
}
else
{
printf("not sure\n");
}
}
return 0;
}