Learn python the hard way Ex48更复杂的用户输入

经过半天的绸缪，敲击，检错，修正，终于完成了第48小节作者留的作业，虽然代码看起来很糟糕，但是收获不小，我是菜鸟，大神勿喷啊，嘎嘎嘎

#encoding:utf-8
import re


def scan(sentence = None):

    directions = ['north','south','east','west']
    verbs      = ['go','kill','eat']
    stops      = ['the','in','of']
    nouns      = ['bear','princess']
    reward     = []
    global  EN

    if sentence == None:         # 如果是***不传参***，就请求输入
        command = raw_input("Please input your command > ")
        while command == '':    # 如果输入***为空***，就再次请求
            command = raw_input("Please input your command > ")
    else:                       # 如果是***传参***，就用参数作为输入
        command = sentence

    words = command.split()     # 将句子分离为单词序列
    r1 = r"^[0-9]+$"            # 纯数字的正则表达式

    for word in words:
        if re.match(r1,word) != None:# 判断是否能够匹配
            word = int(word)
        if type(word) == str :    # 判断单词是否为***字符串***类型
            for direction in directions:    # 判断单词是否在***方向***列表内
                if direction == word:
                    reward.append(('direction', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for verb in verbs:              # 判断单词是否在***动词***列表内
                if verb == word:
                    reward.append(('verb', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for stop in stops:              # 判断单词是否在***顿词***列表内
                if stop == word:
                    reward.append(('stop', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == True:
                continue

            for noun in nouns:              # 判断单词是否在***名词***列表内
                if noun == word:
                    reward.append(('noun', word))
                    EN = True
                    break
                else:
                    EN = False
            if EN == False:
                reward.append(('error', word))
            
        elif (type(word) == int )or(type(word) == float)\
                or(type(word) == long )or(type(word) == complex):
            reward.append(('number', word))

        else:
            reward.append(('error', word))
            break
    return reward

用nose工具测试结果如下：