程序运行产生SIGABRT信号的原因



（注：SIGABRT信号即signal 6的信号）

一、多次free导致的SIGABRT

#include "stdlib.h"
#include "string.h"
#include "stdio.h

int main()
{
    void *pc = malloc(1024);
    free(pc);
    //free(pc);  //打开注释会导致错误

    printf("free ok!\n");

    return 0;
}

#include "stdlib.h"
#include "string.h"
#include "stdio.h

int main()
{
    void *pc = malloc(1024);
    free(pc);
    //free(pc);  //打开注释会导致错误

    printf("free ok!\n");

    return 0;
}

二、执行abort函数

#include "string.h"
#include "stdio.h"
#include "stdlib.h"

int main()
{
    printf("before run abort!\n");
    abort();
    printf("after run abort!\n");

    return 0;
}

#include "string.h"
#include "stdio.h"
#include "stdlib.h"

int main()
{
    printf("before run abort!\n");
    abort();
    printf("after run abort!\n");

    return 0;
}

三、执行到assert函数

[cpp] view plain copy print ?

#include "string.h"
#include "stdio.h"
#include "assert.h"
#include "stdlib.h"

int main()
{
    printf("before run assert!\n");
#if 0  //该值为0，则报错；为1，则正常
    void *pc = malloc(1024);
#else
    void *pc = NULL;
#endif
    assert( pc != NULL );
    printf("after run assert!\n");

    return 0;
}

转自：http://blog.csdn.net/season_hangzhou/article/details/54926636

#include "string.h"
#include "stdio.h"
#include "assert.h"
#include "stdlib.h"

int main()
{
    printf("before run assert!\n");
#if 0  //该值为0，则报错；为1，则正常
    void *pc = malloc(1024);
#else
    void *pc = NULL;
#endif
    assert( pc != NULL );
    printf("after run assert!\n");

    return 0;
}