牛客网SQL编程题

题目描述

查找当前薪水(to_date=‘9999-01-01’)排名第二多的员工编号emp_no、薪水salary、last_name以及first_name，不准使用order by
CREATE TABLE employees (
emp_no int(11) NOT NULL,
birth_date date NOT NULL,
first_name varchar(14) NOT NULL,
last_name varchar(16) NOT NULL,
gender char(1) NOT NULL,
hire_date date NOT NULL,
PRIMARY KEY (emp_no));
CREATE TABLE salaries (
emp_no int(11) NOT NULL,
salary int(11) NOT NULL,
from_date date NOT NULL,
to_date date NOT NULL,
PRIMARY KEY (emp_no,from_date));

输入描述

无

输出描述

emp_no	salary	last_name	first_name
10009	94409	Peac	Sumant

代码示例

SELECT e.emp_no, MAX(s.salary) AS salary, e.last_name, e.first_name
FROM employees e
	INNER JOIN salaries s ON e.emp_no = s.emp_no
WHERE s.to_date = '9999-01-01'
	AND s.salary NOT IN (
		SELECT MAX(salary)
		FROM salaries
		WHERE to_date = '9999-01-01'
	);