动动手
0.先练练手,把我们的刚开始的那个猜数字小游戏加上界面吧?
import easygui as g
import random
g.msgbox('嗨,欢迎进入第一个界面小游戏!')
secret = random.randint(1,10)
msg = "猜猜我心中的数字是什么(0~10):"
title = "数字小游戏"
guess = g.integerbox(msg, title, lowerbound = 0, upperbound = 10)
while True:
if guess == secret:
g.msgbox('你是我肚里的蛔虫吗!')
break
else:
if guess > secret:
g.msgbox('猜大了呀,再试试')
else:
g.msgbox('猜小了呀,再试试')
guess = g.integerbox(msg, title, lowerbound = 0, upperbound = 10)
g.msgbox('游戏结束,不玩啦!')
1.实现一个用于登记用户账号信息的界面(如果是带*号的必填项,要求一定要有输入并且不能是空格)。
from easygui import *
msg = "输入你的个人信息"
title = "登录界面"
fieldNames = ["账号名*","密码*","地址","联系电话*","邮箱地址"]
fieldValues = [] # 创建一个空列表存放账号信息
fieldValues = multenterbox(msg,title, fieldNames)
# 确保带*号的信息不为空
while 1:
if fieldValues == None:
break
errmsg = ""
for i in range(len(fieldNames)):
if (fieldValues[i].strip() == "") and (fieldNames[i][-1] == "*"):
errmsg = errmsg + ('"%s" 是必填项.\n\n' % fieldNames[i])
if errmsg == "":
break
fieldValues = multenterbox(errmsg, title, fieldNames, fieldValues)
print("个人信息:", fieldValues)
2.提供一个文件浏览框,让用户选择需要打开的文本文件,打开并显示文件内容。
import easygui as g
import os
file_path = g.fileopenbox(default = "*.txt")
with open(file_path) as f:
title = os.path.basename(file_path)
msg = "文件【%s】的内容如下:" %title
text = f.read()
g.textbox(msg, title, text)
3.在上一题的基础上增强功能:当用户点击“OK”按钮的时候,比较当前文件是否修改过,如果修改过,则提示“覆盖保存”、“放弃保存”或“另存为…”并实现相应的功能。
import easygui as g
import os
file_path = g.fileopenbox(default = "*.txt")
with open(file_path) as old_file:
title = os.path.basename(file_path)
msg = "文件【%s】的内容如下:" %title
text = old_file.read()
text_after = g.textbox(msg, title, text)
if text != text_after[:-1]:
#textbox的返回值会追加一个换行符
choice = g.buttonbox("文件已修改,请做出选择:", "警告", ("覆盖保存", "放弃保存", "另存为…"))
if choice == "覆盖保存":
with open(file_path, "w") as old_file:
old_file.write(text_after[:-1])
if choice == "放弃保存":
pass
if choice == "另存为…":
another_path = g.filesavebox(default = ".txt")
if os.path.splitext(another_path)[1] != '.txt':
another_path += '.txt'
with open(another_path, "w") as new_file:
new_file.write(text_after[:-1])
4.写一个程序统计你当前代码量的总和,并显示离十万行代码量还有多远?
要求一:递归搜索各个文件夹
要求二:显示各个类型的源文件和源代码数量
要求三:显示总行数与百分比
import easygui as g
import os
def show_result(start_dir):
lines = 0
total = 0
text = ""
for i in source_list:
lines = source_list[i]
total += lines
text += "【%s】源文件 %d 个,源代码 %d 行\n" % (i, file_list[i], lines)
title = '统计结果'
msg1 = '您目前共写了 %d 行代码,完成进度:%.2f %%\n离10万行代码还差 %d 行,请继续努力!' % (total, total/1000, 100000 - total)
msg2 = '您目前共写了 %d 行代码,完成进度:%.2f %%\n超额完成 %d 行,真棒!' % (total, total/1000, total - 100000)
if total <= 100000:
g.textbox(msg1, title, text)
else:
g.textbox(msg2, title, text)
def calc_code(file_name):
lines = 0
with open(file_name) as f:
print('正在分析文件:%s ...' % file_name)
try:
for each_line in f:
lines += 1
except UnicodeDecodeError:
pass
return lines
def search_file(start_dir):
os.chdir(start_dir)
for each_file in os.listdir(os.curdir):
ext = os.path.splitext(each_file)[1]
if ext in target:
lines = calc_code(each_file)
try:
file_list[ext] += 1
except KeyError:
file_list[ext] = 1
try:
source_list[ext] += lines
except KeyError:
source_list[ext] = lines
if os.path.isdir(each_file):
search_file(each_file)
os.chdir(os.pardir)
target = ['.c', '.cpp', '.py', '.cc', '.java','.pas', '.asm']
file_list = {}
source_list = {}
g.msgbox("请打开您存放所有代码的文件夹......", "统计代码量")
path = g.diropenbox("请选择你的代码库:")
search_file(path)
show_result(path)