60.View the Exhibit and examine the structure of CUSTOMERS table.

60.View the Exhibit and examine the structure of CUSTOMERS table.
Evaluate the following query:
SQL>SELECT cust_id, cust_city FROM customers WHERE 
cust_first_name NOT LIKE 'A_%g_%' AND
cust_credit_limit BETWEEN 5000 AND 15000 AND
cust_credit_limit NOT IN (7000, 11000) AND
cust_city NOT BETWEEN 'A' AND 'B';

Which statement is true regarding the above query?

A.It executes successfully.
B.It produces an error because the condition on the CUST_CITY column is not valid.
C.It produces an error because the condition on the CUST_FIRST_NAME column is not valid.
D.It produces an error because conditions on the CUST_CREDIT_LIMIT column are not valid.
答案：A
A:正确
B：错误

cust_city NOT BETWEEN 'A' AND 'B',这种是进行的ascii进行的判断,比如

SQL> select 1 from dual where 'B' between 'A' and 'C';

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‘B' between ’A' and ‘C'  相当于  ’B' >= 'A' and  'B' <='C'

在比如

SQL> select 1 from dual where 'ABC' between 'A' and 'C';

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SQL> select 1 from dual where 'CBA' between 'A' and 'C';


no rows selected

第一个有结果而第二个没有，这是因为‘ABC' 首字母为A，和between 的开头A相等，因此开始判断第二个字母，由于between开始的字符 没有第二个字母所以符合

第二个没有结果是因此，第一个为C和and的C相等，然后 判断第二个，第二个为B ，但是and的C没有第二个字符结果给大了

SQL> select 1 from dual where 'CBA' between 'A' and 'CC';


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这个就符合了，因此B

C：错误

cust_first_name NOT LIKE 'A_%g_%',这种匹配的是A开头，然后任意字符中间有个g，然后是任意字符，比如
SQL> select 1 from dual where 'Awwwwwgwwww' LIKE 'A_%g_%';


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D：错误