mysql根据出生年月日计算年龄大小

SELECT age,DATE_FORMAT(NOW(),'%Y/%m/%d'),(YEAR(NOW())-YEAR(age)-1) + ( DATE_FORMAT(age, '%m%d') <= DATE_FORMAT(NOW(), '%m%d') ) AS 年龄  FROM  users AS u

另外大家可以研究下下面三种计算函数

SELECT  TIMESTAMPDIFF(YEAR, '2000-12-27', CURDATE());
SELECT FLOOR(DATEDIFF(CURDATE(), '2000-12-27')/365.2422); 
SELECT ROUND(DATEDIFF(CURDATE(),'2000-12-27')/365.2422);

 

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