在PostgreSQL里,with子句提供了一种方法写一个大的查询中使用的辅助报表与查询。它有助于打破复杂和大型查询简单易读的形式。
1. 建表postgres=# create table tb9(id serial primary key,name character varying, parentid integer);
CREATE TABLE
postgres=# \d tb9
Table "public.tb9"
Column | Type | Modifiers
----------+-------------------+--------------------------------------------------
id | integer | not null default nextval('tb9_id_seq'::regclass)
name | character varying |
parentid | integer |
Indexes:
"tb9_pkey" PRIMARY KEY, btree (id)
2. 插入测试数据
postgres=# insert into tb9 values(generate_series(1,5),'john',0);
INSERT 0 5
postgres=# insert into tb9 values(6,'john1',1);
INSERT 0 1
postgres=# insert into tb9 values(7,'john2',1);
INSERT 0 1
postgres=# insert into tb9 values(8,'john11',6);
INSERT 0 1
postgres=# select * from tb9;
id | name | parentid
----+--------+----------
1 | john | 0
2 | john | 0
3 | john | 0
4 | john | 0
5 | john | 0
6 | john1 | 1
7 | john2 | 1
8 | john11 | 6
(8 rows)
3. with子句
postgres=# with t as (select * from tb9 where parentid=1) select count(0) from t;
count
-------
2
(1 row)
postgres=# with t(a,b,c) as (select * from tb9 where parentid=1) select a,b,c from t;
a | b | c
---+-------+---
6 | john1 | 1
7 | john2 | 1
(2 rows)
4. 多个with子句的结合使用
postgres=# with t1 as (select * from tb9),t2 as(select * from tb9 where parentid=1) select t1.* from t1,t2 where t2.id=t1.parentid;
id | name | parentid
----+--------+----------
8 | john11 | 6
(1 row)
5. 递归
postgres=# with recursive t as(select id,name,parentid from tb9 where id=1 union all select k.id,k.name,k.parentid from tb9 k,t where t.id=k.parentid) select * from t;
id | name | parentid
----+--------+----------
1 | john | 0
6 | john1 | 1
7 | john2 | 1
8 | john11 | 6
9 | john21 | 7
(5 rows)