怎么用Python写一个三体的气候模拟程序

所谓三体气候模拟，就是将太阳出现的情况进行分类讨论，然后将其呈现出来。比如说一颗太阳就是恒纪元，两颗太阳可能是二日凌空或二日连珠，三颗太阳也可能是三日凌空或三日连珠。只要明白了这一点，这个三体气候模拟的程序就很好写了。

在写程序前，得先导入一个库。由于三体问题的复杂性，我们姑且将三颗太阳出现的概率定位三分之一，也就是说要用到随机的方法。所以我们这里需要导入random库中的randint——随机数函数。

from random import randint

在插入完random库后，要先确定几个变量。由于三体世界有三颗太阳，且可能出现在不同的位置，所以可以定义变量：

# 其中0代表该太阳为飞星，1代表该太阳出现
sun1 = randint(0, 1)
sun2 = randint(0, 1)
sun3 = randint(0, 1)
# 1~3分别代表不同的位置，如果位置相同就是连珠
sun1_pos = randint(1, 3)
sun2_pos = randint(1, 3)
sun3_pos = randint(1, 3)

除了这几个基础变量，还需要两个用来输出气候类型和纪元类型的变量：weather和era_mode

weather = ""
era_mode = ""

因为后面将这两个变量以文字形式输出，所以是String的形式

完成变量设定后，就该考虑三体世界的气候情况了。

依照书中的描述，我们可以分为（恒纪元就不讨论了）：三颗飞星（即没有太阳）、二日凌空、二日连珠、三日凌空和三日连珠

这么一来，就可以开始写程序了。

首先是没有太阳，即三颗飞星情况：

if sun1 == sun2 == sun3 == 0:   # 三颗太阳都没有出现
    weather = "三颗飞星"
    era_mode = "乱纪元"
    print(era_mode, weather)    # 输出气候情况

然后检测是否为恒纪元，即一颗太阳：

if sun1 == 1 and sun2 == sun3 == 0:
    era_mode = "恒纪元"
    print(era_mode)
elif sun2 == 1 and sun1 == sun3 == 0:
    era_mode = "恒纪元"
    print(era_mode)
elif sun3 == 1 and sun1 == sun2 == 0:
    era_mode = "恒纪元"
    print(era_mode)

 接着是三颗太阳的情况：

if sun1 == sun2 == sun3 == 1:
    if sun1_pos == sun2_pos == sun3_pos:
        weather = "三日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "三日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)

 最后是两颗太阳的情况，就相对比较麻烦了：

if sun1 == sun2 == 1:
    if sun1_pos == sun2_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)
elif sun1 == sun3 == 1:
    if sun1_pos == sun2_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)
elif sun2 == sun3 == 1:
    if sun2_pos == sun3_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)

 

注意，这个从三颗飞星、一颗太阳、三颗太阳、两颗太阳的顺序是不能打乱的，否则就会出现气候判断不准的情况，因为这个程序的运行是从上往下走的，是线性的。举个例子，如果现在有三颗太阳，而两颗太阳的判定在三颗太阳的判定之前，程序运行时就会出现只输出二日连珠或二日凌空的情况，而不会输出三日凌空或三日连珠。

当然，你也可以用其他的方法让气候判断的排序改变，比如可以全部把这些判断啥的写道不同的函数里在进行判断，但在这里就不加以赘述。

最后把全部代码放上来：

from random import randint

# 其中0代表该太阳为飞星，1代表该太阳出现
sun1 = randint(0, 1)
sun2 = randint(0, 1)
sun3 = randint(0, 1)
# 1~3分别代表不同的位置，如果位置相同就是连珠
sun1_pos = randint(1, 3)
sun2_pos = randint(1, 3)
sun3_pos = randint(1, 3)

weather = ""
era_mode = ""

if sun1 == sun2 == sun3 == 0:   # 三颗太阳都没有出现
    weather = "三颗飞星"
    era_mode = "乱纪元"
    print(era_mode, weather)    # 输出气候情况
elif sun1 == 1 and sun2 == sun3 == 0:
    era_mode = "恒纪元"
    print(era_mode)
elif sun2 == 1 and sun1 == sun3 == 0:
    era_mode = "恒纪元"
    print(era_mode)
elif sun3 == 1 and sun1 == sun2 == 0:
    era_mode = "恒纪元"
    print(era_mode)
elif sun1 == sun2 == sun3 == 1:
    if sun1_pos == sun2_pos == sun3_pos:
        weather = "三日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "三日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)
elif sun1 == sun2 == 1:
    if sun1_pos == sun2_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)
elif sun1 == sun3 == 1:
    if sun1_pos == sun2_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)
elif sun2 == sun3 == 1:
    if sun2_pos == sun3_pos:
        weather = "二日连珠"
        era_mode = "乱纪元"
        print(era_mode, weather)
    else:
        weather = "二日凌空"
        era_mode = "乱纪元"
        print(era_mode, weather)

总行数不超过100行，还是挺精简的

如果要查看太阳的生成，可以在添加完变量后（即上述代码的11行处）添加：

print("sun1: %u , sun2: %u , sun3: %u" % (sun1, sun2, sun3))
print("sun1_pos: %u , sun2_pos: %u , sun3: %u" % (sun1_pos, sun2_pos, sun3_pos))