卜若的代码笔记-unity系列-unity里面的数学-第一章：求两个向量的夹角

1.本文的应用背景在比如要去解决一个动态转身的问题

 

 

2.已知两个向量如何求解夹角？

 

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class MathTool : MonoBehaviour {


    public static float getAngl(Vector3 vec1, Vector3 vec2)
    {
        float sita = dot(vec1, vec2) / (module(vec1) * module(vec2));  
        float angel = Mathf.Acos(sita);
        angel = angel * Mathf.Rad2Deg;
        Debug.Log(angel);
        return angel;
    }

    void Update()
    {
        if(Input.GetKeyDown(KeyCode.S))
        {


            Debug.Log(getAngl(new Vector3(1,0,0),new Vector3(0.5f,0.5f,0)));
        }
      
 
    
    }
    /// 

    /// 返回两个向量的点乘结果
    /// 
    /// 
    public static float dot(Vector3 vec1, Vector3 vec2)
    {
        return vec1.x * vec2.x + vec1.y * vec2.y + vec1.z * vec2.z;
    
    }

    public static float module(Vector3 vec1)
    {
        return Mathf.Sqrt(vec1.x * vec1.x + vec1.y * vec1.y + vec1.z * vec1.z);
    
    }



}