#非等值连接 #案例1:查询员工的工资和工资级别 SELECT salary, grade_level FROM employees e, job_grades g WHERE salary BETWEEN g.lowest_sal AND g.highest_sal AND g.grade_level = 'A'; #3.自连接 #案例:查询员工名和上级的名称 SELECT e.employee_id, e.last_name, m.employee_id, m.last_name FROM employees e, employees m WHERE e.manager_id = m.employee_id; #作业 #1、显示员工表的最大工资,工资平均值 SELECT Max(salary), avg(salary) FROM employees; #查询员工表的 employee_id, job_id, last_name,按 department_id降序, salary升序 SELECT employee_id, job_id, last_name FROM employees ORDER BY department_id DESC, salary; #三、查询员工表的bid中包含a和e的,并且a在e的前面 SELECT job_id FROM employees WHERE job_id LIKE '%a%e%'; /*四、已知表 student,里面有id(学号),name,gradeId(年级编号) 已知表grade,里面有id(年级编号),name(年级名) 已知表result,里面有id, score,studentNo(学号) 要求查询姓名、年级名、成绩 */ SELECT s. NAME, g. NAME, r.score FROM student s, grade g, result r WHERE s.id = r.studentNo AND s.gradeId = g.id; #五、显示当前日期,以及去前后空格,截取子字符串的函数 SELECT NOW() SELECT trim(字符 FROM ''); SELECT substr(str, startIndex); SELECT sunstr (str, startIndex, length); #1.显示所有员工的姓名,部门号和部门名称 USE myemployees; SELECT last_name, d.department_id, d.department_name FROM employees e, departments d WHERE e.department_id = d.department_id; #2.查询90号部门员工的job_id和90号部门的1ocation id USE myemployees; SELECT e.job_id, d.location_id FROM employees e, departments d WHERE e.department_id = d.department_id AND e.department_id = 90; #3选择所有有奖金的员工的last_name,department_name,location_id,city SELECT last_name, department_name, l.location_id, city FROM employees e, departments d, locations l WHERE l.location_id = d.location_id AND e.department_id = d.department_id AND e.commission_pct IS NOT NULL; #4.选择city在Toronto工作的员工的last_name,job_id,department_id,department_name SELECT last_name, job_id, d.department_id, department_name FROM employees e, departments d, locations l WHERE e.department_id = d.department_id AND l.location_id = d.location_id AND city = 'Toronto'; #5.查询每个工种、每个部门的部门名、工种名和最低工资 SELECT department_name, job_title, MIN(salary) FROM employees e, departments d, jobs j WHERE e.department_id = d.department_id AND e.job_id = j.job_id GROUP BY department_name, job_title; #6.查询每个国家下的部门个数大于2的国家编引 SELECT country_id, COUNT(*) 部门个数 FROM departments d, locations l WHERE d.location_id = l.location_id GROUP BY country_id HAVING 部门个数 > 2; #7.选择指定员工的姓名,员工号,以及他的管理者的姓名和员工号,结果类似于下面的格式 #employees Emp# manager Mar# #kochhar 101 king 100 SELECT e.last_name employees, e.employee_id "Emp#", m.last_name manager, m.employee_id "Mgr#" FROM employees e, employees m WHERE e.manager_id = m.employee_id AND e.last_name = 'kochhar'; CREATE TABLE job_grades ( grade_level VARCHAR (3), lowest_sal INT, highest_sal INT ); INSERT INTO job_grades VALUES ('A', 1000, 2999); INSERT INTO job_grades VALUES ('B', 3000, 5999); INSERT INTO job_grades VALUES ('C', 6000, 9999); INSERT INTO job_grades VALUES ('D', 10000, 14999); INSERT INTO job_grades VALUES ('E', 15000, 24999); INSERT INTO job_grades VALUES ('F', 25000, 40000);