描述
给出一棵二叉树，返回其节点值的层次遍历（逐层从左往右访问）
样例
给一棵二叉树{3,9,20,#,#,15,7}：
3
/ \
9 20
/ \
15 7
返回他的分层遍历结果：
[
[3],
[9,20],
[15,7]
]
挑战
挑战1：只使用一个队列去实现它
挑战2：用BFS算法来做
代码
GitHub 的源代码，请访问下面的链接：
https://github.com/cwiki-us/java-tutorial/blob/master/src/test/java/com/ossez/lang/tutorial/tests/lintcode/LintCode0069LevelOrderTest.java
package com.ossez.lang.tutorial.tests.lintcode;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
import org.junit.Test;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import com.ossez.lang.tutorial.models.TreeNode;
/**
*
* 69
*
- @see
* "https://www.cwiki.us/display/ITCLASSIFICATION/Binary+Tree+Level+Order+Traversal">https://www.cwiki.us/display/ITCLASSIFICATION/Binary+Tree+Level+Order+Traversal
*
- @see
* "https://www.lintcode.com/problem/binary-tree-level-order-traversal">https://www.lintcode.com/problem/binary-tree-level-order-traversal
*
*
*
*
* @author YuCheng
*
*/
public class LintCode0069LevelOrderTest {
private final static Logger logger = LoggerFactory.getLogger(LintCode0069LevelOrderTest.class);
/**
*
*/
@Test
public void testMain() {
logger.debug("BEGIN");
String data = "{3,9,20,#,#,15,7}";
TreeNode tn = deserialize(data);
System.out.println(levelOrder(tn));
}
/**
* Deserialize from array to tree
*
* @param data
* @return
*/
private TreeNode deserialize(String data) {
// NULL CHECK
if (data.equals("{}")) {
return null;
}
ArrayList
data = data.replace("{", "");
data = data.replace("}", "");
String[] vals = data.split(",");
// INSERT ROOT
TreeNode root = new TreeNode(Integer.parseInt(vals[0]));
treeList.add(root);
int index = 0;
boolean isLeftChild = true;
for (int i = 1; i < vals.length; i++) {
if (!vals[i].equals("#")) {
TreeNode node = new TreeNode(Integer.parseInt(vals[i]));
if (isLeftChild) {
treeList.get(index).left = node;
} else {
treeList.get(index).right = node;
}
treeList.add(node);
}
// LEVEL
if (!isLeftChild) {
index++;
}
// MOVE TO RIGHT OR NEXT LEVEL
isLeftChild = !isLeftChild;
}
return root;
}
private List
Queue
List
// NULL CHECK
if (root == null) {
return rs;
}
queue.offer(root);
while (!queue.isEmpty()) {
int length = queue.size();
List
for (int i = 0; i < length; i++) {
TreeNode curTN = queue.poll();
list.add(curTN.val);
if (curTN.left != null) {
queue.offer(curTN.left);
}
if (curTN.right != null) {
queue.offer(curTN.right);
}
}
rs.add(list);
}
return rs;
}
}
点评
这个程序可以使用队列的广度优先算法来进行遍历。
需要注意的是，因为在输出结果的时候需要按照层级来进行输出，那么需要考虑的一个算法就是二叉树的层级遍历算法。
这个算法要求在遍历的时候记录树的层级。
https://www.cwiki.us/display/ITCLASSIFICATION/Binary+Tree+Level+Order+Traversal