PreparedStatement 查询 In 语句 setArray 等介绍。

ps = conn.prepareStatement("SELECT tid,jdp_response FROM jdp_tb_trade WHERE tid IN (?) ORDER BY created DESC");
ps.setString(1, "3152892500240988,3152893300713891");

本人如上使用 prepareStatement 结果只能查询出来一条数据,也不报错,调试了一天啊!!!尝试了各种办法 都没成功。后来突发奇想知道原因了;我如上设置,最终执行的sql语句可能是:

SELECT tid,jdp_response FROM jdp_tb_trade WHERE tid IN ('3152892500240988,3152893300713891') ORDER BY created DESC 

而我想真正执行的SQL语句是:
SELECT tid,jdp_response FROM jdp_tb_trade WHERE tid IN (3152892500240988,3152893300713891) ORDER BY created DESC

PreparedStatement 查询 In 语句 setArray 等介绍。_第1张图片

 

那么由于in()里 有多个参数,所以需要多个?号 多个setLong才行。即in(?,?,?.....)
怎么办呢;
看了很多网上的做法,我自己写出了我自己的写法如下:

            String tids = "3152892500240988,3152893300713891";
            String[] tidsAry = tids.split(",");
            StringBuffer stringBuffer = new StringBuffer("?");
            for (int i = 0; i <= tidsAry.length - 2; i++)
            {
                stringBuffer.append(",?");
            }
            System.out.println(stringBuffer.toString());
            ps = conn.prepareStatement("SELECT tid,jdp_response FROM jdp_tb_trade WHERE tid IN (".concat(stringBuffer.toString()).concat(") ORDER BY created DESC"));
            System.out.println(tidsAry.length);
            for (int i = 0; i <= tidsAry.length - 1; i++)
            {
                System.out.println(i);
                ps.setLong(i + 1, Long.parseLong(tidsAry[i]));
            }

            ResultSet rs = ps.executeQuery();
            while (rs.next()){

                System.out.println(rs.getString(1));
            }

 


 



转载于:https://www.cnblogs.com/del88/p/6433248.html

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