springboot jpa 实现复杂的sql 如 A and （B or C）

在使用Jpa 查询，想要实现如下sql：

SELECT *
FROM table WHERE id =... AND (already_used = TRUE OR  expire_date < ...) 

原使用：findByIdAndAlreadUsedTrueOrExpireDateBefore()方法，发现jpa实现的是

where id =？ and already_used = true or expire_date < ?

并不是我想要的。
解决方法：
1、使用@Query注解写原生sql来实现，但是如果有分页就比较麻烦
2、将 A and （B or C） 拆分成 A and B or A and C

findByIdAndAlreadUsedTrueOrExpireDateBefore() 
===>
findByIdAndAlreadUsedTrueOrIdAndExpireDateBefore() 

即可，示例如下：

public class Girls {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private long classes;
    private Boolean hasBF;
    private int age;
    private String cupSize;
    private String name;
}   
public interface GirlsDao extends JpaRepository<Girls,Long> {
    List findByClassesAndHasBFTrueOrCupSize(long classes,String cupSize);
    List findByClassesAndHasBFTrueOrClassesAndCupSize(long classes0,long classes1,String cupSize);
}

测试：查找同一个classes下只要hasBF ==True 或cupSize==”B”中满足其中一个条件即可的数据
方法一：

@Test
public void test(){
    List girls = girlsDao.findByClassesAndHasBFTrueOrCupSize(12, "B");
    girls.forEach(System.out::println);
}

结果如下：

Hibernate: select girls0_.id as id1_0_, girls0_.age as age2_0_, girls0_.classes as classes3_0_, girls0_.cup_size as cup_size4_0_, girls0_.hasbf as hasbf5_0_, girls0_.name as name6_0_ from girls girls0_ where girls0_.classes=? and girls0_.hasbf=1 or girls0_.cup_size=?
Girls{id=1, classes=12, hasBF=true, age=18, cupSize='B', name='XI'}
Girls{id=2, classes=12, hasBF=false, age=17, cupSize='B', name='HE'}
Girls{id=3, classes=12, hasBF=true, age=18, cupSize='C', name='HH'}
Girls{id=4, classes=13, hasBF=true, age=16, cupSize='B', name='XX'}

方法二：

@Test
public void contextLoads() {
    List girls = girlsDao.findByClassesAndHasBFTrueOrClassesAndCupSize(12, 12, "B");
    girls.forEach(System.out::println);
}

结果如下：

Hibernate: select girls0_.id as id1_0_, girls0_.age as age2_0_, girls0_.classes as classes3_0_, girls0_.cup_size as cup_size4_0_, girls0_.hasbf as hasbf5_0_, girls0_.name as name6_0_ from girls girls0_ where girls0_.classes=? and girls0_.hasbf=1 or girls0_.classes=? and girls0_.cup_size=?
Girls{id=1, classes=12, hasBF=true, age=18, cupSize='B', name='XI'}
Girls{id=2, classes=12, hasBF=false, age=17, cupSize='B', name='HE'}
Girls{id=3, classes=12, hasBF=true, age=18, cupSize='C', name='HH'}