牛客网数据库7:获取所有非manager员工当前的薪水情况，给出dept_no、emp_no以及salary ，当前表示to_date='9999-01-01'

获取所有非manager员工当前的薪水情况，给出dept_no、emp_no以及salary ，当前表示to_date='9999-01-01'
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

 

 

select de.dept_no,e.emp_no,s.salary
from employees e
 join dept_emp de
on e.emp_no=de.emp_no
 join salaries s
on e.emp_no=s.emp_no
left join dept_manager dm
on de.dept_no=dm.dept_no and de.emp_no=dm.emp_no
where s.to_date='9999-01-01' and dm.dept_no is null and dm.emp_no is null

select de.dept_no,e.emp_no,s.salary
from employees e
 join dept_emp de
on e.emp_no=de.emp_no
 join salaries s
on e.emp_no=s.emp_no
where s.to_date='9999-01-01' and e.emp_no not in (select emp_no from dept_manager)