SQL Basics: Up and Down

*	*
链接	SQL Basics: Up and Down
难度	7kyu
状态	√
日期	2019-4-17

题意

题解1

select 
case when (number1 + number2) mod 2 == 0
then max(number1 , number2)
when (number1 + number2) mod 2 <> 0
then min(number1 , number2)
from numbers

题解2

select 
case
  when sum(number1) % 2 = 1 then min(number1)
  else max(number1)
end as number1
,
case
  when sum(number2) % 2 = 1 then min(number2)
  else max(number2)
end as number2

from numbers