Hive案例--级联报表查询

有如下数据：

A,2015-01,5 A,2015-01,15 B,2015-01,5 A,2015-01,8 B,2015-01,25 A,2015-01,5 C,2015-01,10 C,2015-01,20 A,2015-02,4 A,2015-02,6 C,2015-02,30 C,2015-02,10 B,2015-02,10 B,2015-02,5 A,2015-03,14 A,2015-03,6 B,2015-03,20 B,2015-03,25 C,2015-03,10 C,2015-03,20

 

建表：

create table t_access_times(username string,month string,counts int)

row format delimited fields terminated by ',';

开发脚本：以致最后结果如下：

用户	月份	月总额	累计到当月的总额
A	2015-01	33	33
A	2015-02	10	43
A	2015-03	30	73
B	2015-01	30	30
B	2015-02	15	45

 

首先，查询没人每月的总额

create table t_access_amount

as

select uid,month,sum(times) as amount

from t_access_times

group by uid,month;

将总额表自连接

create table t_tmp

as

select a.amount as a_amount,b.*

from t_access_amount a join t_access_amount b

on a.uid=b.uid;

where a.month <= b.month;

最终结果：

select uid,month,max(amount) as amount, sum(a_amount) as accumulate

from t_tmp

group by  uid,month;