.Net C#向远程服务器Api上传文件

Api服务代码一：

        /// 

        /// 服务器接收接口
        /// 
        [HttpPost]
        [Route("ReceiveFile")]
        public HttpResponseMessage ReceiveFile()
        {
            string result = string.Empty;
            ArrayList list = new ArrayList();
            try
            {
                Stream postStream = HttpContext.Current.Request.InputStream;
                byte[] b = new byte[postStream.Length];

                string postFileName = DNTRequest.GetString("fileName");
                if (string.IsNullOrEmpty(postFileName) && HttpContext.Current.Request["fileName"] != null)
                {
                    postFileName = HttpContext.Current.Request["fileName"];
                }
                string fileExtension = Path.GetExtension(postFileName);
                string dirName = "other";
                if (!string.IsNullOrEmpty(fileExtension))
                {
                    dirName = fileExtension.Substring(fileExtension.LastIndexOf(".") + 1);
                }
                string dir = "/_temp/file/" + dirName + "/" + DateTime.Now.ToString("yyyyMMdd") + "/";
                string fileName = DateTime.Now.ToString("yyyyMMddHHmmss_ffff");
                fileName += fileExtension;
                string filePath = HttpContext.Current.Server.MapPath(dir);
                string saveFilePath = Path.Combine(filePath, fileName);
                string dirPath = dir + fileName;
                list.Add(dirPath);

                if (!Directory.Exists(filePath))
                {
                    Directory.CreateDirectory(filePath);
                }

                FileStream fs = new FileStream(saveFilePath, FileMode.Create);
                byte[] new_b = new byte[1024];
                const int rbuffer = 1024;

                while (postStream.Read(new_b, 0, rbuffer) != 0)
                {
                    fs.Write(new_b, 0, rbuffer);
                }
                postStream.Close();
                fs.Close();
                fs.Dispose();

                if (list.Count > 0)
                {
                    result = DNTRequest.GetResultJson(true, "success", string.Join(",", list.ToArray()));
                }
            }
            catch (Exception ex)
            {
                result = DNTRequest.GetResultJson(false, ex.Message, null);
            }
            HttpResponseMessage responseMessage = new HttpResponseMessage { Content = new StringContent(result, Encoding.GetEncoding("UTF-8"), "text/plain") };
            return responseMessage;
        }

Api服务代码二：

        [HttpPost]
        [Route("ReceiveFileTest")]
        public HttpResponseMessage ReceiveFileTest()
        {
            string result = string.Empty;
            var request = HttpContext.Current.Request;
            try
            {
                if (request.Files.Count > 0)
                {
                    var fileNameList = new List<string>();
                    string dirName = "other";
                    foreach (string f in request.Files)
                    {
                        var file = request.Files[f];

                        string fileExtension = Path.GetExtension(file.FileName).ToLower();
                        string fileName = DateTime.Now.ToString("yyyyMMddHHmmss_ffff");
                        fileName += fileExtension;
                        if (!string.IsNullOrEmpty(fileExtension))
                        {
                            dirName = fileExtension.Substring(fileExtension.LastIndexOf(".") + 1);
                        }
                        string dir = "/_temp/file/" + dirName + "/" + DateTime.Now.ToString("yyyyMMdd") + "/";
                        string filePath = HttpContext.Current.Server.MapPath(dir);
                        if (!Directory.Exists(filePath))
                        {
                            Directory.CreateDirectory(filePath);
                        }
                        string fileSavePath = Path.Combine(filePath, fileName);

                        Stream postStream = file.InputStream;
                        //
                        FileStream fs = new FileStream(fileSavePath, FileMode.Create);
                        byte[] new_b = new byte[1024];
                        const int rbuffer = 1024;

                        while (postStream.Read(new_b, 0, rbuffer) != 0)
                        {
                            fs.Write(new_b, 0, rbuffer);
                        }
                        postStream.Close();
                        fs.Close();
                        fs.Dispose();

                        string dirPath = dir + fileName;
                        fileNameList.Add(dirPath);
                        fileNameList.Add(fileName);
                    }

                    result = DNTRequest.GetResultJson(true, string.Format("{0}:{1}", HttpStatusCode.OK, string.Join(",", fileNameList.ToArray())), null);
                }
                else
                {
                    result = DNTRequest.GetResultJson(false, "请选择上传的文件", null);
                }
            }
            catch (Exception ex)
            {
                result = DNTRequest.GetResultJson(false, ex.Message, null);
            }
            HttpResponseMessage responseMessage = new HttpResponseMessage { Content = new StringContent(result, Encoding.GetEncoding("UTF-8"), "text/plain") };
            return responseMessage;
        }

Ajax提交file代码，调用Api代码一的Script：

此方法后端Api代码一中始终获取不到文件名，所以我在Ajax的url中加了?fileName=fileObj.name，这样调试能走通。为什么Ajax提交时不能获取到文件名，我还在研究。

Ajax提交file代码，调用Api代码一的Html：

    

        
Ajax提交到远程服务器Api
        

            for="ds_host">选择文件
            

                
            
            

                
            
            

                
            
        
    

Form表单提交Post到远程Api代码二中，这个很顺利。下边是Html

"http://localhost:19420/Api/ReceiveFileTest" method="post" enctype="multipart/form-data">
    

        
Form表单提交到远程服务器Api
        
class="form-group">
            class="col-sm-2 control-label" for="ds_host">选择文件
            
class="col-sm-4">
                class="form-control" id="inpFileUrl2" name="inpFileUrl2" type="text" placeholder="上传后返回地址" />
            
            
class="col-sm-4">
                "file" name="file" />
            
            
class="col-sm-2">
                "submit" value="提交" />
            
        
    

 

Api服务部署时需要考虑到客户端提交file时有跨域问题，快捷方法是在IIS中设置Access-Control-Allow-Origin:*，但这样做有安全问题。

网站上传文件大小默认4M，所以网站配置文件中需要设置，如下：

  
    "409600" />
  

服务器IIS上传文件大小也有限制，也要做设置，如下：

  
    
      
        
        "518144000"/>
      
    
  

 

以上是我近2天的研究成果，不算完善还需要改进。

Api中使用了三方框架RestSharp，请在解决方案中找NuGet添加。

外部操作类用到的方法有，一：

        /// 

        /// 拼装JSON
        /// 
        static public string GetResultJson(bool result, string msg, Object data)
        {
            string resultJson = string.Empty;
            Hashtable ht = new Hashtable();
            try
            {
                ht.Add("result", result);
                ht.Add("msg", msg);
                ht.Add("data", data);
            }
            catch (Exception ex)
            {
                ht.Add("result", false);
                ht.Add("msg", ex.Message);
            }
            resultJson = Newtonsoft.Json.JsonConvert.SerializeObject(ht);
            return resultJson;
        }

 注意：Html代码中file控件需要有name=“file”属性，否则提交后Api获取不到file对象，如下。

<input type="file" name="file" />

 

 

第三种方法是form表单提交调用mvc的control，control在调用Api代码二，这个测试失败，能上传文件，但上传的文件不能打开是损坏的，正在想办法解决。

下边是第三种方法的Html代码：

<form action="/Test/UploadFileTest" method="post" enctype="multipart/form-data">
    <fieldset>
        <legend>Form表单提交到本地Controllegend>
        <div class="form-group">
            <label class="col-sm-2 control-label" for="ds_host">选择文件label>
            <div class="col-sm-4">
                <input class="form-control" id="inpFileUrl3" name="inpFileUrl3" type="text" placeholder="上传后返回地址" />
            div>
            <div class="col-sm-4">
                <input type="file" name="file" />
            div>
            <div class="col-sm-2">
                <input type="submit" value="提交" />
            div>
        div>
    fieldset>
form>

下边是第三种方法的Control代码：

        [HttpPost]
        public ActionResult UploadFileTest()
        {
            string result = string.Empty;

            string apiUrl = "http://localhost:19420/Api/ReceiveFileTest";
            string contentType = "application/octet-stream";

            var files = new List<string>();
            foreach (string f in Request.Files)
            {
                var file = Request.Files[f];
                var request = new RestRequest(Method.POST);
                request.AlwaysMultipartFormData = true;
                //request.AddParameter("fileName", file.FileName);
                Stream postStream = file.InputStream;
                byte[] b = new byte[postStream.Length];
                request.AddFile("file", b, file.FileName, contentType);

                var restClient = new RestClient { BaseUrl = new Uri(apiUrl) };
                string res = string.Empty;
                IRestResponse