一个最基础完整版的ajax项目

jsp文件

<%--
  Created by IntelliJ IDEA.
  User: Administrator
  Date: 2018/9/14
  Time: 19:57
  To change this template use File | Settings | File Templates.
--%>
<%@ page contentType="text/html;charset=UTF-8" language="java" %>

  
    
    


  
  
  type="button" onclick="sendHttpRequest()" value="准备好开始爽了吗">
  





java

package com.tjetc.demo;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.PrintWriter;

public class AJAXAction extends HttpServlet {
    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        req.setCharacterEncoding("UTF-8");
        resp.setCharacterEncoding("UTF-8");
        PrintWriter out = resp.getWriter();
        out.print("你通过AJAXAction对我进行了访问爽了吗");
    }
}

WEB.XML

<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0">
 <servlet>
     <servlet-name>AJAXActionservlet-name>
     <servlet-class>com.tjetc.demo.AJAXActionservlet-class>

 servlet>
    <servlet-mapping>
        <servlet-name>AJAXActionservlet-name>
        <url-pattern>/AJAXActionurl-pattern>
    servlet-mapping>
web-app>