将字符串中的标点符号过滤掉

开发中我们有可能会遇到这种情况，就是将字符串中的某个字符去掉

@Test
	public void test() {
		String d = trimPunctuation2("你，好oewefo,21.2!;:、1?dsf");
		System.out.println(d);
	}

	// 将字符串中的标点符号过滤掉
	public static String trimPunctuation2(String str) {
		String punct[] = { ",", ".", "!", "?", ";", ":", "，", "。", "！", "？",
				"；", "：", "、" };
		List punctList = Arrays.asList(punct); // 将String数组转List集合
		StringBuilder result = new StringBuilder();
		for (int i = 0; i < str.length(); i++) {
			Character c = str.charAt(i);
			if (punctList.contains(c.toString())) {

			} else {
				result.append(str.charAt(i));
			}
		}

		return result.toString();
	}

	// 将字符串中的标点符号过滤掉
	public static String trimPunctuation(String str) {
		StringBuilder result = new StringBuilder();
		for (int i = 0; i < str.length(); ++i) {
			char punct[] = { ',', '.', '!', '?', ';', ':', '，', '。', '！', '？',
					'；', '：', '、' };
			boolean need_filter = false;
			for (int j = 0; j < punct.length; ++j) {
				if (punct[j] == str.charAt(i)) {
					need_filter = true;
					break;
				}
			}

			if (!need_filter) {
				result.append(str.charAt(i));
			}
		}

		return result.toString();
	}