为什么80%的码农都做不了架构师?>>>
问题:
Write a SQL query to get the nth highest salary from the Employee
table.
+----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+
For example, given the above Employee table, the nth highest salary where n = 2 is 200
. If there is no nth highest salary, then the query should return null
.
+------------------------+ | getNthHighestSalary(2) | +------------------------+ | 200 | +------------------------+
① 这道题是之前那道Second Highest Salary的拓展,根据之前那道题的做法,我们可以很容易的将其推展为N,根据对Second Highest Salary中①的分析,我们只需要将OFFSET后面的1改为N-1就行了,可以在前面加一个SET N = N - 1,将N先变成N-1。1019 ms
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
SET N = N - 1;
RETURN (
SELECT Salary FROM Employee
GROUP BY Salary
ORDER BY Salary DESC
LIMIT 1
OFFSET N
);
END
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
SET N = N - 1;
RETURN (
SELECT DISTINCT Salary FROM Employee
ORDER BY Salary DESC
LIMIT 1
OFFSET N
);
END
② 根据对Second Highest Salary中④的分析,我们只需要将其1改为N-1即可。2278 ms
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
RETURN (
SELECT MAX(e1.Salary) FROM Employee E1
WHERE N - 1 =
(SELECT COUNT(DISTINCT(E2.Salary)) FROM Employee E2
WHERE E2.Salary > E1.Salary)
);
END