数据结构与算法笔记 lesson 10 栈 二进制转换十进制

使用栈将二进制转换为十进制

    将二进制的每一位从栈里读出再计算

 #include 
 #include
 #include

 #define STACK_INIT_SIZE 20
 #define STACKINCREMENT 10

 typedef char ElemType;
 typedef struct
  {
        ElemType *base;
	ElemType *top;
	int stackSize;
  }sqStack;

   void InitStack(sqStack *s)
  {
	s->base = (ElemType *)malloc(STACK_INIT_SIZE * sizeof(ElemType));
	if (!s->base)
		exit(0);
	s->top = s->base;
	s->stackSize = STACK_INIT_SIZE;
  }

   void Push(sqStack *s, ElemType e) 
  {
	if (s->top - s->base >= s->stackSize)
	{
		s->base = (ElemType*)realloc(s->base, (s->stackSize + STACKINCREMENT) * sizeof(ElemType));
		if (!s->base)
			exit(0);
	}
	*(s->top) = e;
	s->top++;
  }

   void Pop(sqStack *s, ElemType *e)
  {
	if (s->top == s->base)
		return;
	*e = *--(s->top);
  }

  int StackLen(sqStack s)
  {
	return (s.top - s.base);
  }

  int main()
  {
	ElemType c;
	sqStack s;
	int len, i, sum = 0;

	InitStack(&s);

	scanf("%c", &c);//字符一个一个的输入
	while (c!='#')
	{
		Push(&s, c);
		scanf("%c", &c);
	}
	getchar();//过滤回车'\n'

	len = StackLen(s);

	printf("栈的当前容量是：%d\n", len);

	for (i = 0; i < len; i++)
	{
		Pop(&s, &c);
		sum = sum + (c - 48)*pow(2, i);
	}
	printf("转为10进制为%d\n",sum);

	return 0;
  }