题目链接:hdu 5483 Nux Walpurgis
先求一下最小生成树。然后枚举起点,遍历整棵树,维护树边能被替换的最小权值。
#pragma comment(linker, "/STACK:102400000,102400000")
#include
#include
#include
#include
using namespace std;
const int maxn = 3005;
const int inf = 0x3f3f3f3f;
struct Edge {
int u, v, w;
Edge(int u = 0, int v = 0, int w = 0): u(u), v(v), w(w) {}
bool operator < (const Edge& a) const { return w < a.w; }
};
int N, F[maxn], W[maxn], T[maxn];
int E, first[maxn], jump[maxn<<1], linker[maxn<<1], idx[maxn<<1];
vector S;
vector<int> D[maxn];
void addEdge(int u, int v, int w) {
jump[E] = first[u];
linker[E] = v;
idx[E] = w;
first[u] = E++;
}
int find (int x) { return x == F[x] ? x : F[x] = find(F[x]); }
void set(int u, int v, int w) {
if (u > v) swap(u, v);
D[u][v-u-1] = w;
}
int get (int u, int v) {
if (u > v) swap(u, v);
return D[u][v-u-1];
}
void init () {
S.clear();
scanf("%d", &N);
int x;
for (int i = 0; i < N; i++) {
D[i].clear();
for (int j = 1; j < N-i; j++) {
scanf("%d", &x);
D[i].push_back(x);
S.push_back(Edge(i, i+j, x));
}
}
}
void miniTree () {
E = 0;
memset(first, -1, sizeof(first));
for (int i = 0; i < N; i++) F[i] = i;
int n = N;
sort(S.begin(), S.end());
for (int i = 0; i < S.size(); i++) {
int u = S[i].u, v = S[i].v;
if (find(u) != find(v)) {
F[find(u)] = find(v);
addEdge(u, v, n);
addEdge(v, u, n);
set(u, v, inf);
W[n--] = S[i].w;
if (n == 1) break;
}
}
}
int dfs (int u, int fa, int rt, int id, int w) {
// printf("rt=%d fa=%d u=%d %d %d\n", rt, fa, u, id, w);
for (int i = first[u]; i + 1; i = jump[i]) {
int v = linker[i];
if (v == fa) continue;
w = min(w, dfs(v, u, rt, idx[i], get(rt, v)));
}
T[id] = min(T[id], w);
return w;
}
int main () {
int cas;
scanf("%d", &cas);
while (cas--) {
init();
miniTree();
for (int i = 1; i <= N; i++) T[i] = inf;
for (int i = 0; i < N; i++) dfs(i, i, i, 1, inf);
int ans = 0;
for (int i = 2; i <= N; i++) {
if (T[i] != W[i]) ans++;
}
printf("%d\n", ans);
}
return 0;
}