poj2503 map构建字典树

题解:用map很简单的。只是输入很有问题,用scanf反正我是没写运行成功。于是一个字符一个字符的输入。。
#include
#include
#include
#include
#include
using namespace std;

map qq;
map p;

char a[1001],b[1001],c[1001];

int main()
{
    while(1)
    {

        char t;
        if((t=getchar())=='\n')
          break;
        else
        {
            int i=0,j=0;
            a[i++]=t;
            while(1)
            {
               t=getchar();
               if(t==' ')
                  {
                    a[i]='\0';
                    break;
                  }
                else
                   a[i++]=t;
            }
        }
        scanf("%s",b);
        getchar();
        qq[b]=a;
        p[b]=1;
    }
    while(scanf("%s",c)!=EOF)
    {
        if(p[c])
            cout<

Babelfish
Time Limit: 3000MS   Memory Limit: 65536K
Total Submissions: 32988   Accepted: 14189

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

Sample Output

cat
eh
loops

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