之前网上的45道mysql练习题,自己打了一遍,同时发现题目的一些问题,并自己想了一些变种,分享一下
CREATE TABLE student(
sno VARCHAR(20) NOT NULL PRIMARY KEY,
sname VARCHAR(20) NOT NULL,
ssex VARCHAR(20) NOT NULL,
sbirthday datetime,
class VARCHAR(20)
);
CREATE TABLE teacher
(
tno VARCHAR(20) NOT NULL PRIMARY KEY,
tname VARCHAR(20) NOT NULL,
tsex VARCHAR(20) NOT NULL,
tbirthday datetime,
prof VARCHAR(20), # 职称
depart VARCHAR(20) NOT NULL
);
CREATE TABLE course
(
cno VARCHAR(20) NOT NULL PRIMARY KEY,
cname VARCHAR(20) NOT NULL,
tno VARCHAR(20) NOT NULL,
FOREIGN KEY(tno) REFERENCES teacher(tno) # 外键
);
CREATE TABLE score
(
sno VARCHAR(20) NOT NULL,
FOREIGN KEY(sno) REFERENCES student(sno),
cno VARCHAR(20) NOT NULL,
FOREIGN KEY(cno) REFERENCES course(cno),
degree DECIMAL, # 分数
PRIMARY KEY(sno, degree) # 要设置为联合逐渐才行
);
insert into student values('108','曾华','男','1977-09-01','95033');
insert into student values('105','匡明','男','1975-10-02','95031');
insert into student values('107','王丽','女','1976-01-23','95033');
insert into student values('101','李军','男','1976-02-20','95033');
insert into student values('109','王芳','女','1975-02-10','95031');
insert into student values('103','陆君','男','1974-06-03','95031');
insert into teacher values('804','李诚','男','1958-12-02','副教授','计算机系');
insert into teacher values('856','张旭','男','1969-03-12','讲师','电子工程系');
insert into teacher values('825','王萍','女','1972-05-05','助教','计算机系');
insert into teacher values('831','刘冰','女','1977-08-14','助教','电子工程系');
insert into course values('3-105','计算机导论','825');
insert into course values('3-245','操作系统','804');
insert into course values('6-166','数字电路','856');
insert into course values('9-888','高等数学','831');
insert into score values('103','3-245','86');
insert into score values('105','3-245','75');
insert into score values('109','3-245','68');
insert into score values('103','3-105','92');
insert into score values('105','3-105','88');
insert into score values('109','3-105','76');
insert into score values('103','3-105','64');
insert into score values('105','3-105','91');
insert into score values('109','3-105','78');
insert into score values('103','6-166','85');
insert into score values('105','6-166','79');
insert into score values('109','6-166','81');
SELECT sname, ssex, class from student;
SELECT DISTINCT depart FROM teacher;
SELECT * FROM student;
SELECT * FROM score
WHERE degree BETWEEN 60 AND 80;
SELECT * FROM score
WHERE degree in (85, 86, 88);
SELECT * FROM student
WHERE class = '95031' or ssex = '女';
SELECT * FROM student
ORDER BY class DESC;
SELECT * FROM score
ORDER BY cno asc, degree DESC;
SELECT COUNT(*) FROM student
WHERE class = '95301';
SELECT sno, cno, FROM score WHERE degree = (
SELECT max(degree) FROM score);
SELECT sno, cno FROM score ORDER BY degree DESC LIMIT 0,1;
SELECT cno, AVG(degree) FROM score GROUP BY cno;
SELECT cno, AVG(degree) FROM score
WHERE cno LIKE '3%'
GROUP BY cno
HAVING COUNT(sno) >= 2;
SELECT AVG(degree) FROM score
WHERE cno LIKE '3%' AND cno in (
SELECT cno FROM score GROUP BY cno HAVING COUNT(*) >2
);
SELECT sno FROM score
WHERE degree > 70 AND degree < 90;
SELECT sname, cno, degree FROM student, score
WHERE student.sno = score.sno;
SELECT sname, cno, degree FROM student INNER JOIN score
ON student.sno = score.sno;
SELECT sno, cname, degree FROM course, score
WHERE course.cno = score.cno;
select Sname,Cname,Degree from student,course,score
where student.Sno=score.Sno and course.Cno=score.Cno;
SELECT snae, cname, degree FROM student INNER JOIN score ON student.sno = score.sno
INNER JOIN course ON score.cno = course.cno;
SELECT avg(degree) FROM score, student
WHERE student.sno = score.sno and class='95033';
CREATE TABLE grade(low int(3), upp int(3), rank char(1);
insert into grade VALUES(90, 100, 'A');
insert into grade VALUES(80, 89, 'B');
insert into grade VALUES(70, 79, 'C');
insert into grade VALUES(60, 69, 'D');
insert into grade VALUES(0, 59, 'E');
SELECT sno, cno, rank from score, grade where degree BETWEEN low and upp;
select * from score
where degree > (select max(degree) from score where sno = '109' and cno = '3-105')
and cno = '3-105';
select degree from score
where sno in
(
select sno from student
where class = '95033' or '95031'
);
select Sno, Sname, Sbirthday
from student
where year(Sbirthday) in
(
select year(Sbirthday)
from student
where Sno = '108' or '101'
);
select * from score where cno in
(
select cno from course where tno in
(
select tno from teacher where tname = '张旭'
)
);
select cname, degree
from score, course, teacher
where score.cno = course.cno
and teacher.tno = course.tno
and teacher.tname = '张旭';
select tname from teacher
where tno in
(
select tno from course
where cno in
(
select cno from score group by cno having count(cno) > 5
)
)
;
select * from student where class = '95033' or '95031';
select cno, count(cno) as counts from score where degree > 85
group by cno;
select * from score where cno in
(
select cno from course where tno in
(
select tno from teacher where depart = '计算机系'
)
);
select tname, prof, depart from teacher
where prof not in
(
select prof from teacher
group by prof
having count(prof) > 1
);
select cno, sno, degree from score
where cno = '3-105'
and degree > all(select degree from score where cno = '3-245')
order by degree desc;
select sname as name, ssex as sex, sbirthday as birthday from student
union all
select tname as name, tsex as sex, tbirthday as birthday from teacher
;
select tname as name, tsex as sex, tbirthday as birthday from teacher
where tsex='女'
union
select sname as name, ssex as sex, sbirthday as birthday from student
where ssex='女';
select * from score a where degree < (
select avg(degree) as pingjunfen from score b
where a.cno = b.cno
);
select cno, avg(degree) from score
group by cno;
select tname, depart from teacher
where tno in
(
select tno from course
where cno in
(
select distinct cno from score
)
);
select tname, depart from teacher
where tno not in
(
select tno from course
where cno in
(
select distinct cno from score
)
);
select class from student
where ssex='男'
group by class
having count(ssex)>1;
select * from student
where sname not like '王%';
select sname, year(now())-year(sbirthday) as suishu from student;
select max(sbirthday), min(sbirthday) from student;
select * from student order by class desc, sbirthday;
select cno, cname, tname from teacher, course
where course.tno = teacher.tno
and teacher.tsex = '男';
select cno, cname, tname
from teacher
inner join
course
on teacher.tno = course.tno
where teacher.tsex = '男';
select sno, cno, degree from score
order by degree desc
limit 0, 1; # 从第0行开始再追加1条数据
select sno, cno, degree from score
where degree = (
select max(degree) from score
);
select cno, max(degree) from score
group by cno;
select sname from student
where ssex = (
select ssex from student where sname = '李军'
)
and sname != '李军';
select sname from student
where ssex = (
select ssex from student where sname = '李军'
)
and
class = (
select class from student where sname = '李军'
)
and sname != '李军';
select * from score where cno = (
select cno from course where cname = '计算机导论'
)
and
sno in (
select sno from student where ssex = '男'
);