python——圆周率PI的蒙特卡洛算法

#CalPiV2.py
from random import random
from time import perf_counter
DARTS = 1000*1000
hits = 0.0
start = perf_counter()
for i in range(1, DARTS+1):
    x, y = random(), random()
    dist = pow(x ** 2 + y ** 2, 0.5)
    if dist <= 1.0:
        hits = hits + 1
pi = 4 * (hits/DARTS)
print("圆周率值是: {}".format(pi))
print("运行时间是: {:.5f}s".format(perf_counter() - start))

附上公式算法

#CalPiV1.py
pi = 0
N = 100
for k in range(N):
    pi += 1/pow(16,k)*( \
              4/(8*k+1) - 2/(8*k+4) - \
              1/(8*k+5) - 1/(8*k+6) ) 
print("圆周率值是: {}".format(pi))