hdu 1405

The Last Practice

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5415    Accepted Submission(s): 1084


Problem Description
Tomorrow is contest day, Are you all ready?
We have been training for 45 days, and all guys must be tired.But , you are so lucky comparing with many excellent boys who have no chance to attend the Province-Final.

Now, your task is relaxing yourself and making the last practice. I guess that at least there are 2 problems which are easier than this problem.
what does this problem describe?
Give you a positive integer, please split it to some prime numbers, and you can got it through sample input and sample output.
 

Input
Input file contains multiple test case, each case consists of a positive integer n(1
 

Output
For each test case you should output its factor as sample output (prime factor must come forth ascending ), there is a blank line between outputs.
 

Sample Input
 
   
60 12 -1
 
#include
#include
#include
using namespace std;
int n,rec[66666];
int main()
{
    int Cas = 1;
    while(scanf("%d",&n),n>0)
    {
        int x=n;
        memset(rec,0,sizeof(rec));
        if( Cas > 1 )
            puts( "" );
        for(int i=2; i<=n; i++)//从i枚举到n 当除数
        {
            while(n%i==0)//只要n还能除i
            {
                rec[i]++;
                n/=i;//再把n除一把
            }
        }
        printf( "Case %d.\n",Cas++);
        for(int i=2; i<=x; ++i)
            if(rec[i])
                printf("%d %d ",i,rec[i]);
        puts("");
    }
    return 0;
}


Sample Output
 
  
Case 1. 2 2 3 1 5 1 Case 2. 2 2 3 1
Hint
60=2^2*3^1*5^1

你可能感兴趣的:(hdu)